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irakobra [83]
4 years ago
6

Help please ASAP !!!!!

Mathematics
1 answer:
olga2289 [7]4 years ago
7 0
It should be either the last one or the first one but it will probably be the last one.
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Find the coordinates of the midpoint of the segment whose endpoints are R(9, 3) and S(-1, -9).
amm1812

Answer:

(4, -3 )

General Formulas and Concepts:

<u>Pre-Algebra I</u>

  • Order of Operations: BPEMDAS

<u>Algebra I</u>

  • Midpoint Formula: (\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2} )

Step-by-step explanation:

<u>Step 1: Define</u>

R (9, 3)

S (-1, -9)

<u>Step 2: Find midpoint</u>

  1. Substitute:                    (\frac{9-1}{2}, \frac{3-9}{2} )
  2. Subtract:                       (\frac{8}{2}, \frac{-6}{2} )
  3. Divide:                          (4, -3 )
4 0
3 years ago
Which best describes the strength of the correlation, and
denis23 [38]

Answer:

Step-by-step explanation:

the answer is ~ It is a weak negative correlation, and it is likely causal.

7 0
4 years ago
Read 2 more answers
7- H ,0 am An average persons heart beats about 103,680 times a day and solve an equation to find about how many times me average
Mrac [35]
103680÷24=4320
4320÷60=72
=72times/minute
8 0
3 years ago
What is the explicit rule for the geometric sequence?<br> 600, 300, 150, 75, ...
pochemuha

Answer:

Step-by-step explanation:

Hello, this is a geometric sequence so we are looking for a multiplicative factor.

a_0=600\\\\a_1=a_0 \cdot \boxed{\dfrac{1}{2}} = 300 = 600 \cdot \boxed{\dfrac{1}{2}}\\\\a_2=a_1 \cdot \boxed{\dfrac{1}{2}} = 150= 300 \cdot \boxed{\dfrac{1}{2}}\\\\a_3=a_2 \cdot \boxed{\dfrac{1}{2}} = 75 = 150 \cdot \boxed{\dfrac{1}{2}}

So, the explicit formula is for n

\boxed{a_n=a_0\cdot \left(\dfrac{1}{2}\right)^n=600\cdot \left(\dfrac{1}{2}\right)^n}}

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

5 0
3 years ago
Solve 2 log3 x + log3 5 =125​
zepelin [54]

Answer:

x = √(3^125/ 5)

approx 2.9552445 * 10^29.

Step-by-step explanation:

2 log3 x + log3 5 =125​

log3 x^2 + log3 5 = 125

log3 (5x^2) = 125

3^125 = 5x^2

x^2 = 3^125/ 5

x = √(3^125/ 5)

This is a huge number

An approximation of it is 2.9552445 * 10^29.

3 0
3 years ago
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