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tensa zangetsu [6.8K]
4 years ago
7

Help with 4&6 please c:

Physics
1 answer:
8090 [49]4 years ago
8 0
#6=7 I can't see 4 we get turnt up
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When discharging, what percentage of the starting voltage will the capacitor reach after 5rc?
Ahat [919]

When discharging equivalent of 0% starting voltage will the capacitor reach after 5RC.

V(t) = V0e-t/RC = V0b initially.

<h3>What is capacitor?</h3>
  • In an electric field, a capacitor is a device that stores electrical energy. It has two terminals and is a passive electrical component.
  • Capacitance refers to a capacitor's effect.
  • The terminals in a capacitor are connected to two metal plates that are spaced apart by a dielectric, a non-conducting material.
  • Two pieces of aluminum foil, along with a piece of paper, can be used to create a capacitor (and some electrical clips).
  • It won't have a lot of storage capacity, so it won't be a great capacitor, but it will still function.
<h3>What are the different types of capacitors?</h3>

The numerous kinds of capacitors and their applications.

  • Frequently utilized in radio tuning circuits is air.
  • Mylar: The material most frequently used in timer circuits for clocks, alarms, and counting.
  • Good for high-voltage applications is glass.
  • Ceramic is used in X-ray, MRI, and other high-frequency devices.
  • a powerful capacitor fuels hybrid and electric vehicles.

Learn more about capacitors here:

brainly.com/question/17584935

#SPJ4

6 0
2 years ago
HEY CAN ANYONE PLS PLS PLS ANSWER DIS!!!!!!!!!!!!!!!
zhenek [66]
What do you need help with?
7 0
3 years ago
Explain why when landing on a firm surface after a fall you should not land with stiff legs.
Digiron [165]

While lending on a surface, we should bend our knees

to provide more time to the velocity change thus decresing the net force on the legs.

transfers a part of reactionary force to thick thigh and calf muscles whicch act as dampers absorbing a part of energy and provides cushioning effect.

Explanation:

We know that Force equal Mass times acceleration.

Acceleration equals the change in velocity per unit time. Hence if the time involved in velocity change is large, resultant acceleration would be less. Hence the resulting force would also be of less magnitude.

The above explanation owes to the act of bending of knees while jumping.

When we jump and simultaneously land, we fall with a force equalling “mass of our body * gravity”. Upon our landing, on the ground, the reactionary force is transmitted to our legs.

Considering our legs are stiff and straight, the force travels quickly through the bones and muscle without sufficient change in the velocity. Hence, we experience nearly the same force on our bones as a result of which bones some-times buckle.

A safer way to land is Landing while folding of the legs. By folding our legs, we give force extra time to travel through the bended section of knee bones. During the travel, the force interacts with thick thigh and calf muscles which act as dampers and absorbs some amount of force.  

By bending, we also increase the time thus decreasing acceleration, hence the force on legs. Thus, by the dual effect of increasing time and damping effect out legs are saved from the excessive buckling effect and remain safe.

6 0
4 years ago
A 68 kg rock climbers 320 m above the ground the sun is down or up at 1.5 m/s using the ground as a reference point determine th
pochemuha

Answer:

213.5 kJ

Explanation:

Mechanical energy= kinetic energy + potential energy= KE+PE=0.5mv^{2}+mgh= m(0.5v^{2}+gh) where m is the mass of rock climber, v is the velocity, g is acceleration due to gravity and h is the height.

By substitution where 68 Kg is m, 320 m is h, 1.5 m/s is v and 9.81 is g then

Mechanical energy=68(0.5\times 1.5^{2}+9.81\times 320)=213542.1 J\approx 213.5 kJ

8 0
3 years ago
I WILL CHOOSE YOU AS THE BRAINIEST PLEASE ANSWER MY QUESTION
Brilliant_brown [7]

Answer:

It's like the Earth pulling on you and keeping you on the ground. That pull is gravity at work. Every object in the universe that has mass exerts a gravitational pull, or force, on every other mass. The size of the pull depends on the masses of the objects.

Explanation:

5 0
4 years ago
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