Answer :
x = -1.43
Explanation :
As given ,
The first box has a height (x+5) has a square base with side x
So, the Length and Breadth of the box are x and x respectively.
Now,
The volume of first box = Length×Breadth×Height
= (x).(x).(x+5)
= x²(x+5)
⇒The volume of first box = x²(x+5)
Now,
Given that , the second box with height (x+2) has a square base with side (x+5).
So, the Length and Breadth of the box are (x+5) and (x+5) respectively.
Now,
The volume of second box = Length×Breadth×Height
= (x+5). (x+5).(x+2)
= (x+5)²(x+2)
⇒The volume of second box = (x+5)²(x+2)
Now,
Given that, the two boxes have the same volume
⇒x²(x+5) = (x+5)²(x+2)
⇒x² = (x+5)(x+2)
⇒x² = x² + 2x + 5x + 10
⇒x² - x² = 7x + 10
⇒0 = 7x + 10
⇒ 7x = -10
⇒ x = -
= -1.43
⇒ x = -1.43
As volume of first box = x²(x+5) = (-1.43)²(-1.43+5) = 7.30 ≈ 7
As volume of second box = (x+5)²(x+2) = (-1.43+5)²(-1.43+2) = 7.26 ≈ 7
At x = -1.43, Volume of both the boxes are same.
The expression:

gives the distance traveled by the aircraft in t hours, so, for t = 6:
ANSWER: -57
14+{−2+3[1+3(−6−2)]}
= 14+{−2+3[1+3(-8)]}
= 14+{−2+3[1+(-24)]}
= 14+{−2+3[1-24]}
= 14+{−2+3[-23]}
= 14+{−2+[-69]}
= 14+{−2-69}
= 14+(-71)
= 14 - 71
= -57