What expression is equivalent to 4.8+2.2w-1.4w+2.4

How many seconds will light leaving Los Angeles take to reach the following locations (a) San Francisco (about 500km), (b) Londo

kondor19780726 [428]

Answer:

a) It takes 0.0017s for the light to reach San Francisco.

b) It takes 0.033s for the light to reach London.

c) It takes 1.334s for the light to reach Mars.

d) It takes 149.7s for the light to reach Venus.

Step-by-step explanation:

Here we can solve this problem by using this following formula:

$s = \frac{d}{t}$

In which s is the speed(in km/s), d is the distance(in km) and t is the time(in s).

The light speed is 299 792 458 m / s = 299,792.458 km/s, so $s = 299,792.458$

(a) San Francisco (about 500km)

Find t when $d = 500$ . So

$s = \frac{d}{t}$

$299,792.458 = \frac{500}{t}$

$299,792.458t = 500$

$t = \frac{500}{299,792.458}$

$t = 0.0017s$

It takes 0.0017s for the light to reach San Francisco.

b) London(about 10,000km)

Find t when $d = 10,000$ . So

$s = \frac{d}{t}$

$299,792.458 = \frac{10,000}{t}$

$299,792.458t = 10,000$

$t = \frac{10,000}{299,792.458}$

$t = 0.033s$

It takes 0.033s for the light to reach London.

(c) the Moon (400,000km)

Find t when $d = 400,000$ . So

$s = \frac{d}{t}$

$299,792.458 = \frac{400,000}{t}$

$299,792.458t = 400,000$

$t = \frac{400,000}{299,792.458}$

$t = 1.334s$

It takes 1.334s for the light to reach Mars.

(d) Venus (0.3 A.U. from Earth at its closest approach).

Each A.U. has 149,59,7871 km.

So 0.3 A.U. = 0.3*(149,597,871) = 44,879,361.3. This means that $d = 44,879,361.3$ . So:

$s = \frac{d}{t}$

$299,792.458 = \frac{44,879,361.3}{t}$

$299,792.458t = 44,879,361.3$

$t = \frac{44,879,361.3}{299,792.458}$

$t = 149.7s$

It takes 149.7s for the light to reach Venus.

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Denny rode his bicycle miles in the morning. Then he rode miles in the afternoon. How far did he ride his bicycle altogether?

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How many miles did he ride each time?? Just add them up

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SashulF [63]

Im confused with your question the picture will not pop up

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4 years ago

1) What is the equation, in point-slope form, for a line that goes through (8,−4) and has a slope of −5/6 ?

labwork [276]

Answer:

The answers are:

1) y + 4 = -5/6(x - 8), which is A, the first option.

2) y - 1 = 5/6(x + 8), which is D, the last option.

3) y + 1 = 6/11(x + 4), which is option C, the third option

4) - y + 3 = -12/7(x - 5), which is option B, the second from the top

5) Plot these points on a graph:

(-1, 5 1/2)

(0, 5 1/4)

(1, 5)

(2, 4 3/4)

Step-by-step explanation:

Question 1:

y - y1 = m(x - x1)

y - (-4) = -5/6(x - 8)

y + 4 = -5/6(x - 8), which is A, the first option.

Question 2:

y - y1 = m(x - x1)

y - 1 = 5/6(x - (-8))

y - 1 = 5/6(x + 8), which is D, the last option.

Question 3:

m = (y - y1)/(x - x1)

m = (5 - (-1)) / (7 - (- 4))

m = (5 + 1) / (7 + 4)

m = 6 / 11

Use the point slope equation and (-4, -1), substitute:

y - y1 = m(x - x1)

y - (-1) = 6/11(x - (-4))

y + 1 = 6/11(x + 4), which is option C, the third option

Question 4:

m = (y - y1)/(x - x1)

m = (-3 - 9)/(5 - (- 2))

m = -12 / (5 + 2)

m = -12/7

Use the point slope equation and (5, -3), substitute:

y - y1 = m(x - x1)

y - (-3) = -12/7(x - 5)

y + 3 = -12/7(x - 5), which is option B, the second from the top

Question 5:

Solve for y, then calculate a few points, graph those points:

y - 4 = -1/4(x - 5)

y - 4 = -1/4x + 5/4

y = -1/4x + 5/4 + 4

y = -1/4x + 5/4 + 16/4

y = -1/4x + 21/4

Solve for x = -1, 0, 1, 2:

f(-1) = -1/4(-1) + 21/4 = 1/4 + 21/4 = 22/4 = 5 1/2, giving point (-1, 5 1/2)

f(0) = 21/4 or 5 1/4 giving point (0, 5 1/4)

f(1) = -1/4 + 21/4 = 20/4 = 5, giving point (1, 5)

f(2) = -1/4(2) + 21/4 = -2/4 + 21/4 = 19/4 or 4 3/4, giving point (2, 4 3/4)

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Please help please please please please

sasho [114]

Explanation is $^{}$ in a file

bit. $^{}$ ly/3gVQKw3

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