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Eduardwww [97]
3 years ago
6

The surface area of the solid is about ____ inches squared

Mathematics
1 answer:
Dafna11 [192]3 years ago
5 0

Answer:

Surface area of the whole figure=  320.28inch^2

Step-by-step explanation:

The surface area of the figure :

Surface area of the cylinder(excluding top)+Surface area of the cone(excluding bottom)

Radius of the cylinder=3 inch     and  Height of cylinder=13 inch

Surface area of the cylinder with one circular face

                                    =2\pi rh+\pi r^2

As,     \pi =\frac{22}{7}= 3.14

   =(2*3.14*3*13)+(3.14*3*3)\\\\=244.92+28.26\\\\=273.18inch^2

Surface area of the cone excluding  base:

                =\pi *r*l

l= slant height=5 inch       r= radius= 3 inch

Surface area of the cone =3.14*3*5

                                        =47.1inch^2

Total surface area of the whole figure=273.18+47.1

                                                           =  320.28inch^2

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Answer:

a + b + c = \pi \\  =  > c=  \pi - a - b \\  <  =  >  \tan(c)  =  \tan(\pi - a - b)  =  -\tan(a + b)

Step-by-step explanation:

we have:

\tan(a)  +  \tan(b)  +  \tan(c)  \\  =  \tan(a)  +  \tan(b)  -  \tan(a + b)  \\  =  \tan( a)  +  \tan(b)  -  \frac{ \tan(a) +  \tan(b)  }{1 -  \tan(a)  \tan(b) }  \\  =  \frac{ ( \tan(a) +  \tan(b)  ) \tan(a) \tan(b)  }{ \tan(a) \tan(b)  - 1 } (1)

we also have:

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from (1)(2) => proven

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