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Sophie [7]
3 years ago
12

Please help me with question 19

SAT
2 answers:
Anit [1.1K]3 years ago
6 0

I think it’s the third option... but don’t count on it

Verizon [17]3 years ago
3 0

Answer: You tried.

Explanation:

- points, good job buddy

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Soon Yi loves to bake, and she is making flaky pastry. Soon Yi starts with a layer of dough 222 millimeters (\text{mm})(mm)left
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When the dough is folded, it increases by a constant factor. We can model the growth of the thickness using the exponential growth model

T(n)=T_0(1+r)^n

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Initial thickness, T_0 = 2mm

Growth factor, r =8%=0.08

We want to find the smallest number of times Soon Yi will have to roll and fold the dough so that the resulting dough is at least 2.5mm.

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2(1+0.08)^n\geq 2.5\\2(1.08)^n\geq 2.5\\$Divide both sides by 2$\\\dfrac{2(1.08)^n}{2}\geq \dfrac{2.5}{2}\\\\1.08^n\geq 1.25\\\\$Change to logarithm form\\n \geq \log_{1.08}1.25\\\\n\geq \dfrac{\log 1.25}{\log 1.08} \\\\n\geq 2.9

Therefore, the smallest number of times Soon Yi will have to roll and fold the dough so that the resulting dough is at least 2.5mm thick is 3.

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