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igor_vitrenko [27]
3 years ago
6

The minimum of the graph of a quadratic function is located at (-1,2) . the point (2,20) is also shown on the parabola . which f

unction represents the situation?

Mathematics
2 answers:
Monica [59]3 years ago
5 0

Answer:

Step-by-step explanation:

Given that The minimum of the graph of a quadratic function is located at (-1,2)

This implies that parabola is open up.

Hence parabola would have equaiton of the form

y-2 = 4a(x+1)^2

To find a:

We use the fact that the parabola passes through (2,20)

Substitute x=2 and y =20

20-2 = 4a(2+1)^2\\18 =36a\\a = 0.5

Hence equation would be

y-2 = 2(x+1)^2

Gekata [30.6K]3 years ago
4 0
The complete question in the attached figure

we know that
the equation of a parabola is
y=a(x-h)²+k
where
(h,k) is the vertex   --------> (h,k)--------> (-1,2)
so
y=a(x+1)²+2

point (2,20)
for x=2
y=20
20=a(2+1)²+2--------> 20=a*9+2--------> 9*a=18---------> a=2

the equation of a parabola is
y=a(x+1)²+2-------> y=2(x+1)²+2

therefore

the answer is the option
<span>C) f(x) = 2(x + 1)2 + 2</span>

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