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docker41 [41]
3 years ago
14

At Wyman Shipping, 140 employees work during the day shift. At night, the crew is 2/5 the size of the day shift. How many worker

s are scheduled to work the night shift?
Mathematics
2 answers:
viva [34]3 years ago
8 0

Answer:

for night shift = 2/5 × 140= 2× 28= 56

rosijanka [135]3 years ago
3 0

Answer:

The number of employees working in the night shift is 56.

Step-by-step explanation:

This problem can be solved using linear equation in one variable. In this equation, the unknown value is taken on one side of the equal sign, and the known values are taken on the other side of the equal sign.

The known values form an expression which is computed to find the unknown value.

The equation includes all the given values and variable is substituted for the unknown value, which is to be computed.

Here, the number of employees that work during the day shift is given. The fraction of employees working in night shift is given.

Total number of employees working in the night shift is to be computed. Hence, variable will be substituted for the number of employees working in the night shift.

Given that the number of employees working in the night shift is \frac{2}{5} of the number of employees working in the day shift.

The different values to be taken in the equation are as follows.

number of employees working in the day shift = 140

number of employees working in the night shift = n

The expression to find the unknown value, i.e., number of employees working in the night shift, is given below.

number of employees working in the night shift = \frac{2}{5} of the number of employees working in the day shift

The linear equation will be formed as shown.

n = 140 \times \frac{2}{5}

n = \frac{280}{5}

n = 56

Therefore, the number of employees working in the night shift is found to be 56.

The total number of employees working during both the shifts, when required, can be found out by adding the number of employees working in the day shift and the number of employees working in the night shift.

The total number of employees, overall, is 56 + 140 = 196.

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2 years ago
A.)List the 4 steps outlined in the lesson on solving equations.
aleksley [76]
1.) Solve for x:
5 x + 7 = 3 x + 21

Subtract 3 x from both sides:
(5 x - 3 x) + 7 = (3 x - 3 x) + 21

5 x - 3 x = 2 x:
2 x + 7 = (3 x - 3 x) + 21

3 x - 3 x = 0:
2 x + 7 = 21

Subtract 7 from both sides:
2 x + (7 - 7) = 21 - 7

7 - 7 = 0:
2 x = 21 - 7

21 - 7 = 14:
2 x = 14

Divide both sides of 2 x = 14 by 2:
(2 x)/2 = 14/2

2/2 = 1:
x = 14/2

The gcd of 14 and 2 is 2, so 14/2 = (2×7)/(2×1) = 2/2×7 = 7:
Answer:  x = 7

____________________________________________________________

2.)  Solve for x:
3 x - 2 (5 - x) = 3 x - 3 (x - 10)

-2 (5 - x) = 2 x - 10:
2 x - 10 + 3 x = 3 x - 3 (x - 10)

Grouping like terms, 3 x + 2 x - 10 = (3 x + 2 x) - 10:
(3 x + 2 x) - 10 = 3 x - 3 (x - 10)

3 x + 2 x = 5 x:
5 x - 10 = 3 x - 3 (x - 10)

-3 (x - 10) = 30 - 3 x:
5 x - 10 = 30 - 3 x + 3 x

3 x - 3 x = 0:
5 x - 10 = 30

Add 10 to both sides:
5 x + (10 - 10) = 10 + 30

10 - 10 = 0:
5 x = 30 + 10

30 + 10 = 40:
5 x = 40

Divide both sides of 5 x = 40 by 5:
(5 x)/5 = 40/5

5/5 = 1:
x = 40/5

The gcd of 40 and 5 is 5, so 40/5 = (5×8)/(5×1) = 5/5×8 = 8:

<span>Answer: x = 8

_________________________________________________________

3.) Solve for x:</span>
5 (x + 1) = 3 (2 x + 3) + 5

3 (2 x + 3) = 6 x + 9:
5 (x + 1) = 6 x + 9 + 5

Grouping like terms, 6 x + 5 + 9 = 6 x + (9 + 5):
5 (x + 1) = 6 x + (9 + 5)

9 + 5 = 14:
5 (x + 1) = 6 x + 14

Expand out terms of the left hand side:
5 x + 5 = 6 x + 14

Subtract 6 x from both sides:
(5 x - 6 x) + 5 = (6 x - 6 x) + 14

5 x - 6 x = -x:
-x + 5 = (6 x - 6 x) + 14

6 x - 6 x = 0:
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Subtract 5 from both sides:
(5 - 5) - x = 14 - 5

5 - 5 = 0:
-x = 14 - 5

14 - 5 = 9:
-x = 9

Multiply both sides of -x = 9 by -1:
(-x)/(-1) = -9
(-1)/(-1) = 1:

<span>Answer: x = -9</span>
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Answer: Only one.

Step-by-step explanation:

We are given that in a triangle two side lengths of 10 centimeters and 8 centimeters. The angle between the sides measures 40°.

Suppose there is also a triangle with the same measures.

Then both the triangles are congruent by SAS congruence postulate.

Thus, every triangle with the given measurement are congruent to each other by SAS postulate.

Therefore, only one triangle can be possible with the given measurement.

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