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Vikki [24]
3 years ago
13

Equations from tables Plzz help

Mathematics
1 answer:
Serggg [28]3 years ago
6 0
1. Initial value: 10
Rate of change: 3
Equation: y + 3

2. Initial value: 3
Rate of change: 3
Equation: y + 3

3. Initial value: 8
Rate of change: -2
Equation: y - 2

The initial value is the y-coordinate when x is equal to 0.
The rate of change is the difference between one point to the next immediate point.
The equation shows the rate of change.
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There were thirteen friends playing a video game online when six players quit.If each player left had eight lives how many lives
Lorico [155]
They had 56 lives in total

Explanation: if there were thirteen friends to begin with and six quit that would leave them with 7 friends. If those seven remaining friends each had 8 lives, you multiply those 7 friends by 8 lives which would get 56.

If all thirteen friends were still in the game then they would have 104 lives all together.
5 0
2 years ago
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Last week, De swam five miles farther than three times the distance his father swam. De swam 23 miles last week. Choose the equa
melomori [17]

Answer:

3m+5 equals 23

Step-by-step explanation:

If De swam 5 miles longer than three times what his dad seam then you would make his father's distance m and plug in the numbers.

4 0
2 years ago
Solve 152x = 36. Round to the nearest ten-thousandth. 1.7509 2.6466 0.6616 1.9091
Vlad [161]
The answer is 0.6616
Hope it helped :)
6 0
3 years ago
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HELP WITH THIS NUMBER PROBLEM PLZ:)
salantis [7]
I believe you would take 127.5 and divide it by 8.5, try that and see if that works, hope this helps!
3 0
4 years ago
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Please please please help and solve this with steps, much help needed thank you :) 20 points for this!
leonid [27]

Answer:

y=\sqrt{\frac{x^4-6x^2+12x+c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+c_1}{2}}

(Please vote me Brainliest if this helped!)

Step-by-step explanation:

\frac{dy}{dx}y=x^3+2x-5x+3

\mathrm{First\:order\:separable\:Ordinary\:Differential\:Equation}

  • \mathrm{A\:first\:order\:separable\:ODE\:has\:the\:form\:of}\:N\left(y\right)\cdot y'=M\left(x\right)

1. \mathrm{Substitute\quad }\frac{dy}{dx}\mathrm{\:with\:}y'\:

y'\:y=x^3+2x-5x+3

2. \mathrm{Rewrite\:in\:the\:form\:of\:a\:first\:order\:separable\:ODE}

yy'\:=x^3-3x+3

  • N\left(y\right)\cdot y'\:=M\left(x\right)
  • N\left(y\right)=y,\:\quad M\left(x\right)=x^3-3x+3

3. \mathrm{Solve\:}\:yy'\:=x^3-3x+3:\quad \frac{y^2}{2}=\frac{x^4}{4}-\frac{3x^2}{2}+3x+c_1

4. \mathrm{Isolate}\:y:\quad y=\sqrt{\frac{x^4-6x^2+12x+4c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+4c_1}{2}}

5. \mathrm{Simplify}

y=\sqrt{\frac{x^4-6x^2+12x+c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+c_1}{2}}

7 0
3 years ago
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