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liubo4ka [24]
4 years ago
15

answer to three friends each create 4 bags of starter bread dough. after ten days, each of those four bags is then divided into

four more bags of dough. how many days pass before 192 bags of dough are created
Mathematics
1 answer:
vlabodo [156]4 years ago
7 0
The answer is 20 days, we can solve this in following way:
Each friend creates 4 bags of dough and after ten days four bags divided into four more bags means:
3 friends x 4 bags = 12 bags  and 12 bags  x 4 = 48 bags
so in next 10 days, the 48 bags will be further divided into 4, so 
48 x 4 = 192 bags
10 days  + next 0 days  = 20 days
so 20 days is the answer.
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The function f(h)=m(1/2)^h gives the mass, m, of a radioactive substance remaining after h half-lives. Cobalt-60 has a half-life
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Answer:

Third choice:

                f(x)=50(0.877)^{10};13.5mg

Explanation:

<u />

<u>1. Data:</u>

<u />

  • Function:

                f(h)=m(1/2)^h

  • Cobalt-60's half-life: 5.3 years

  • Initial mass of cobalt-60:  50 mg

<u>2. Unknown: </u>

<u />

  • equation for the mass of cobalt-60 remaining after 10 years = ?

  • mass remaining =?

<u>3. Solution</u>

<em>Half-life</em> is the time it takes a sample to  decay to half of its initial amount. It is considered constant. Hence, when one half-life passes, the sample has decayed to 50% of the original amount; when two half-lives pass, the sample has decayed to (1/2)×(1/2) = 1/4 = 25%; when three half-lives have elapsed, the sample has decayed to (1/2)³ = 1/8 = 12.5% of its original amount, and so on.

Then, the amound of a sample remaining is calculated as the original amount times (1/2) raised to the number of half-lives elapsed, which is what the given function,  f(h)=m(1/2)^h models.

You just must substitute the data into the function to get the answer to the question:

            f(x)=50(0.5)^{(10/5.3)}

Where, 50 is the original mass of 50g, 0.5 is equal to 1/2, and 10/5.3 gives the number of half-lives (the number of times that 5.3 years is contained in 10 years).

<u>Simplifying:</u>

f(x)=50(0.5)^{(10/5.3)}=50((0.5)^{(1/5.3})^{10}\approx50(0.877)^{10}

Which corresponds to the third choice of the list.

<u>Computing:</u>

               f(x)\approx50(0.877)^{10}=13.5

Which also corresponds to the third choice.

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