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JulijaS [17]
3 years ago
15

(8*10^7)(2*10^6) simplify the expression and write in scientific notation

Mathematics
1 answer:
lesya [120]3 years ago
8 0
Grouping similar factors together makes this easier:

(8)(2)(10^7)(10^6) = 16(10^13) = 1.6(10^14)
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What is the solution to this system of equations?
antoniya [11.8K]

Answer:

c

Step-by-step explanation:

Since both equations express y in terms of x we can equate the right sides

3x + 5 = - x + 3 ( add x to both sides )

4x + 5 = 3 ( subtract 5 from both sides )

4x = - 2 ( divide both sides by 4 )

x = - 0.5

substitute x = - 0.5 in either of the 2 equations

using y = - x + 3 then y = 0.5 + 3 = 3.5

solution is (- 0.5, 3.5 ) → c


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The Department of Agriculture is monitoring the spread of mice by placing 100 mice at the start of the project. The population,
uranmaximum [27]

Answer:

Step-by-step explanation:

Assuming that the differential equation is

\frac{dP}{dt} = 0.04P\left(1-\frac{P}{500}\right).

We need to solve it and obtain an expression for P(t) in order to complete the exercise.

First of all, this is an example of the logistic equation, which has the general form

\frac{dP}{dt} = kP\left(1-\frac{P}{K}\right).

In order to make the calculation easier we are going to solve the general equation, and later substitute the values of the constants, notice that k=0.04 and K=500 and the initial condition P(0)=100.

Notice that this equation is separable, then

\frac{dP}{P(1-P/K)} = kdt.

Now, intagrating in both sides of the equation

\int\frac{dP}{P(1-P/K)} = \int kdt = kt +C.

In order to calculate the integral in the left hand side we make a partial fraction decomposition:

\frac{1}{P(1-P/K)} = \frac{1}{P} - \frac{1}{K-P}.

So,

\int\frac{dP}{P(1-P/K)} = \ln|P| - \ln|K-P| = \ln\left| \frac{P}{K-P} \right| = -\ln\left| \frac{K-P}{P} \right|.

We have obtained that:

-\ln\left| \frac{K-P}{P}\right| = kt +C

which is equivalent to

\ln\left| \frac{K-P}{P}\right|= -kt -C

Taking exponentials in both hands:

\left| \frac{K-P}{P}\right| = e^{-kt -C}

Hence,

\frac{K-P(t)}{P(t)} = Ae^{-kt}.

The next step is to substitute the given values in the statement of the problem:

\frac{500-P(t)}{P(t)} = Ae^{-0.04t}.

We calculate the value of A using the initial condition P(0)=100, substituting t=0:

\frac{500-100}{100} = A} and A=4.

So,

\frac{500-P(t)}{P(t)} = 4e^{-0.04t}.

Finally, as we want the value of t such that P(t)=200, we substitute this last value into the above equation. Thus,

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This is equivalent to \frac{3}{8} = e^{-0.04t}. Taking logarithms we get \ln\frac{3}{8} = -0.04t. Then,

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So, the population of rats will be 200 after 25 months.

6 0
3 years ago
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lord [1]

Answer:

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Step-by-step explanation:

All you have to do is multiply 1/5 x 3 for the three days Monday, Tuesday and Wednesday and that gets you 3/5 or as 1/5 of a km is 0.2 you have to multiply 0.2 x 3 and you get 0.6 which is equivalent to 3/5

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