Answer:
16.5 square units
Step-by-step explanation:
You are expected to integrate the function between x=1 and x=4:
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<em>Additional comment</em>
If you're aware that the area inside a (symmetrical) parabola is 2/3 of the area of the enclosing rectangle, you can compute the desired area as follows.
The parabolic curve is 4-1 = 3 units wide between x=1 and x=4. It extends upward 2.25 units from y=4 to y=6.25, so the enclosing rectangle is 3×2.25 = 6.75 square units. 2/3 of that area is (2/3)(6.75) = 4.5 square units.
This region sits on top of a rectangle 3 units wide and 4 units high, so the total area under the parabolic curve is ...
area = 4.5 +3×4 = 16.5 . . . square units
It is the first graph. The median of the number list is 14. The Q1 is 9 ((7+11)/2) and the Q3 is 17 ((19+15)/2) the two outliers are 6 and 21
Answer:
x = 28
Step-by-step explanation:
It gives you the value of the midsegment, which is 16. So you need to set up the equation as:
x + 4 = 2 × 16
You're multiplying 16 (the midsegment) by 2, because the it is <em>half</em> of x + 4, and you need to be able to set both parts of the equation equal to each other.
x + 4 = 32
Then, subtract 4 from both sides:
x + 4 = 32
-4 -4
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This gives you the answer of:
x = 28
You can set up a ratio as follows:
Solve for x by cross-multiplying:
Since we need the answer in mm and right now we have it in feet, we need a conversion ratio. After googling it, the conversion ratio is: 1ft = 304.8mm
So, the answer is
14326.64 mm.
Answer:
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Step-by-step explanation:
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