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Fofino [41]
2 years ago
8

What is the momentum of a 2 kg shopping cart if it's moving at a speed of 5 m/s

Physics
1 answer:
anastassius [24]2 years ago
8 0

Momentum = (mass) x (speed)

                   =  (2 kg)  x  (5 m/s)

                   =       10 kg-m/s

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If you measured all the energy related to motion and all the stored energy in the particles of a substance, which would you be m
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If you measured all the energy related to motion and all the stored energy in the particles of a substance, you would be measuring the thermal energy of the particles. If there is movement of the particles, they are also releasing energy in the form of heat.

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If a car's mass is 439 kg, what is its weight on earth?
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The correct answer is B.
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The velocity of the wave involved in the Doppler effect:
Margarita [4]

The Doppler Effect provides the equation for the calculation of apparent frequency:

f=fo[vo/(vo-vr)] 

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4 0
3 years ago
Read 2 more answers
A 55 kg person falling with a velocity of 0.6
siniylev [52]

Answer:

What are we supposed to find, if it is kinetic energy then this is the solution.

K.E=1/2mv^2

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M=mass

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Explanation:

3 0
2 years ago
The drag on a pitched baseball can be surprisingly large. Suppose a 145 g baseball with a diameter of 7.4 cm has an initial spee
kupik [55]

Answer:

<h2>Part A)</h2><h2>Acceleration of the ball is 10.1 m/s/s</h2><h2>Part B)</h2><h2>the final speed of the ball is given as</h2><h2>v_f = 35.3 m/s</h2>

Explanation:

Part a)

As we know that drag force is given as

F = \frac{C_d \rho A v^2}{2}

C_d = 0.35

A = \frac{\pi d^2}{4}

A = \frac{\pi(0.074)^2}{4}

A = 4.3 \times 10^{-3} m^2

v = 40.2 m/s

so we have

F = \frac{0.35\times 1.2 (4.3 \times 10^{-3})(40.2)^2}{2}

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a = \frac{F}{m}

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Part B)

As per kinematics we know that

v_f^2 - v_i^2 = 2 a d

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v_f = 35.3 m/s

4 0
3 years ago
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