The cost of running the lightbulb A for 30 days at 0.110 per KWh is 1.98
<h3>How to determine the energy </h3>
We'll beging by calculating the energy used by lightbulb A. This can be obtained as follow:
- Power (P) = 25 watts = 25 / 1000 = 0.025 KW
- Time (t) = 30 days = 30 × 24 = 720 h
- Energy (E) =?
E = Pt
E = 0.025 × 720
E = 18 KWh
<h3>How to determine the cost for running the bulb for 30 days</h3>
The cost of running the bulb for 30 days can be obtained as follow:
- Cost per KWh = 0.11
- Energy (E) = 18 KWh
- Cost =?
Cost = energy × Cost per KWh
Cost = 18 × 0.11
Cost = 1.98
Lean more about buying electrical energy:
brainly.com/question/16963941
#SPJ4
Answer:
9.8m/s^2 down (option C)
Explanation:
The only acceleration acting on this motion case in the acceleration due to gravity: 9.8 m/s^2 in the downwards direction.
Answer:
Answer:
4 ms
Explanation:
initial velocity, u = 75 m/s
final velocity, v = 0
distance, s = 15 cm = 0.15 m
Let the acceleration is a and the time taken is t.
Use third equation of motion
v² = u² + 2 a s
0 = 75 x 75 - 2 a x 0.15
a = - 18750 m/s^2
Use first equation of motion
v = u + at
0 = 75 - 18750 x t
t = 4 x 10^-3 s
t = 4 ms
thus, the time taken is 4 ms.
Explanation:
initial speed of the stuntman is given as
angle of inclination is given as
now the components of the velocity is given as
here it is given that the ramp on the far side of the canyon is 25 m lower than the ramp from which she will leave.
So the displacement in vertical direction is given as
by solving above equation we have
Now in the above interval of time the horizontal distance moved by it is given by
since the canyon width is 77 m which is less than the horizontal distance covered by the stuntman so here we can say that stuntman will cross the canyon.
Answer:
β2= β1+10*f
Explanation:
comparing β2 and β1, it is said that β2 is increased by a factor of f.
for each factor of f, there is a 10*f dB increase.
therefore if the β1 is increases by an intensity of factor f
the new intensity would be β1+ 10*f
