Answer:
5365 N
Explanation:
v = Final velocity = 23 m/s
u = Initial velocity = -14 m/s (opposite direction)
m = Mass of ball = 145 g
t = Time taken = 1 ms
Impulse is given by
Impulse is also given by
The magnitude of the average force exerted by the bat on the ball is 5365 N
Answer:
616.3 rad/s²
Explanation:
Given that
t= 1.46 s
Initial angular velocity ,ωi = 0 rad/s
Final angular velocity ωf= 27000 rev/min
Angular speed in the rad/s given as
Now by putting the values
ωf=900 rad/s
We know that (if acceleration is constant)
ωf=ωi + α t
α=Angular acceleration
900 = 0 + α x 1.46
Therefore the acceleration will be 616.3 rad/s²
Answer:
Explanation:
Mass of block=10 kg
Applied horizontal force =F=20 N
Friction force=f=10 N
We have to find the acceleration of block.
Net force=Applied horizontal force-friction force
Where F= Horizontal force
f=Friction force
m=Mass of object
a=Acceleration of object
Hence, the acceleration of the block=