Find the radius of a sphere with a volume of 4.5π cubic centimeters.

Find the volume of this prism 8cm to 9cm to 11cm

vladimir2022 [97]

Answer:

V = 792 m3

I am kinda guessing on this since you didn't provide a unit or label what the height, width, and length are. Also you should specify what prism...

7 0

3 years ago

Read 2 more answers

Suppose you have developed a scale that indicates the brightness of sunlight. Each category in the table is 4 times brighter tha

raketka [301]

According to the developed scale, a radiant day is <u>16 times</u> brighter than a dim day.

We assume the brightness of a dim day to be x.

According to the developed scale, the brightness of an illuminated day will be 4 times that of a dim day.

Thus, the brightness of an illuminated day = 4*the brightness of a dim day = 4x.

According to the developed scale, the brightness of a radiant day will be 4 times that of an illuminated day.

Thus, the brightness of a radiant day = 4*the brightness of an illuminated day = 4*4x = 16x.

Now, the ratio of the brightness of a radiant day to the brightness of a dim day = 16x:x = 16x/x = 16:1.

Thus, according to the developed scale, a radiant day is <u>16 times</u> brighter than a dim day.

Learn more about the developed scale at

brainly.com/question/4970963

#SPJ1

The question provided is incomplete. The complete question is:

"Suppose you have developed a scale that indicates the brightness of sunlight. Each category in the table is 4 times brighter than the next lower category. For example, a day that is dazzling is 4 times brighter than a day that is radiant. How many times brighter is a radiant day than a dim day?

Dim=2

Illuminated=3

Radiant=4

Dazzling=5"

8 0

1 year ago

Can someone help me please

soldier1979 [14.2K]

Step-by-step explanation:

c >= 2

that means any value of c greater or equal to 2 is a valid solution. so, yes, 2 is a solution for this.

c < 2

that means any value of c smaller than 2 is a valid solution. so, no, 2 is not smaller than 2, so it is not a solution.

c < 3

that means any value of c smaller than 3 is a valid solution. so, yes, 2 is smaller than 3, so 2 is a solution.

3 < c

that means any value of c, for that 3 is smaller, is a valid solution. our in other words, any value for c larger than 3 is a valid solution. so, no, 2 is not larger than 3, so it is not a solution.

-8 < c

that means any value of c, for that -8 is smaller, is a valid solution. our in other words, any value for c larger than -8 is a valid solution. so, yes, 2 is larger than -8, so it is a solution.

5 0

2 years ago

Collin Buys a TV for £720 depreciate at a rate of 4% per year how much will it be worth in three years

belka [17]

Answer:

The worth of the TV after 3 years is £809.90208

Step-by-step explanation:

The answer to given question can be found from the anual depreciation formula and solving for the Future Value (F. V.) of the machine

The given parameters of the TV are;

The amount at which Collin buys the TV, P = £720

The rate at which the TV depreciates at, R = 4%

The number of years the depreciation is applied, T = 3 years

The amount the TV is worth after three years, 'A', is given as follows;

$A = P \cdot \left(1 + \dfrac{R}{100} \right )^T$

By plugging in the known values, we have;

$A = 720 \cdot \left(1 + \dfrac{4}{100} \right )^3 = 809.90208$

The amount the TV is worth after three years, A = £809.90208

8 0

3 years ago

In a city council election, 2,445 votes were cast for one of the candidates. if the candidate received at least one third of the

Nookie1986 [14]

<h2>ANSWER:</h2>

<u><em>A total of 7,335</em></u>

Step-by-step explanation:

<u><em>You need to multiply 2,445 x 3 to get your answer.</em></u>

<u><em /></u>

<h3><u><em>Thank you for asking this great question need any other help please let me know by commenting below I'd be glad to help.</em></u></h3><h3><u><em /></u></h3><h3><u><em> I'd also greatly appreciate you if you mark me as brainliest and click that thanks button.( optional )</em></u></h3><h3><u><em /></u></h3><h3><u><em>Your brainly friend ( lauralit1 )</em></u></h3>

5 0

3 years ago