Answer:
y
=
4
5
x
−
15
Step-by-step explanation:
Answer:
a) r₁₂ = 104.36
In general, rₙ = arⁿ⁻¹
b)
- rabbit food consumed during the 10th year is approximately 832 pounds
- rabbit food consumed in total for the 1st through 10th years is approximately 5265 pounds
Step-by-step explanation:
Given that:
r1 = 30 and a farm grows by 12%
a = 30 and the common ratio r = 1.12
now
n r
1 30.00
2 33.60
3 37.63
4 42.15
5 47.21
6 52.87
7 59.21
8 66.32
9 74.28
10 83.19
11 93.18
12 104.36
Therefore r₁₂ = 104.36
In general, rₙ = arⁿ⁻¹
b)
if each rabbit consume 10 lbs of rabbit food each year
n r food consumed(lbs)
1 30.00 300
2 33.60 336
3 37.63 376
4 42.15 422
5 47.21 472
6 52.87 529
7 59.21 592
8 66.32 663
9 74.28 743
10 83.19 832
total 5265
Therefore, the rabbit food consumed during the 10th year is approximately 832 pounds
And the rabbit food consumed in total for the 1st through 10th years is approximately 5265 pounds
Answer:
24
Step-by-step explanation:
If she did all 3of them today then you subtract a day from each one then it would look like this
5+4+15=24
Answer:
5.6 days
Step-by-step explanation:
We are given;
Initial Mass; N_o = 25 g
Mass at time(t); N_t = 25/2 = 12.5 (I divide by 2 because we are dealing with half life)
k = 0.1229
Formula is given as;
N_t = N_o•e^(-kt)
Plugging in the relevant values;
12.5 = 25 × e^(-0.1229t)
e^(-0.1229t) = 12.5/25
e^(-0.1229t) = 0.5
(-0.1229t) = In 0.5
-0.1229t = -0.6931
t = -0.6931/-0.1229
t = 5.6 days
