Answer:
#Molecules XeF₆ = 2.75 x 10²³ molecules XeF₆.
Explanation:
Given … Excess Xe + 12.9L F₂ @298K & 2.6Atm => ? molecules XeF₆
1. Convert 12.9L 298K & 2.6Atm to STP conditions so 22.4L/mole can be used to determine moles of F₂ used.
=> V(F₂ @ STP) = 12.6L(273K/298K)(2.6Atm/1.0Atm) = 30.7L F₂ @ STP
2. Calculate moles of F₂ used
=> moles F₂ = 30.7L/22.4L/mole = 1.372 mole F₂ used
3. Calculate moles of XeF₆ produced from reaction ratios …
Xe + 3F₂ => XeF₆ => moles of XeF₆ = ⅓(moles F₂) = ⅓(1.372) moles XeF₆ = 0.4572 mole XeF₆
4. Calculate number molecules XeF₆ by multiplying by Avogadro’s Number (6.02 x 10²³ molecules/mole)
=> #Molecules XeF₆ = 0.4572mole(6.02 x 10²³ molecules/mole)
= 2.75 x 10²³ molecules XeF₆.
Answer:
c)
Explanation:
don't understand properly but it is c) cause they go through gens
Answer:
Taking reading of the volume level of liquid in a buret while it is inclined leading to parallax error
Explanation:
Practices that will not help you make accurate volume reading on a buret are
1. Leaving air bubbles buret tip or in the stopcock
2. Error due to parallax: Taking volume reading while looking at the scale of an inclined buret. Looking down the buret gives it an appearance of a higher reading than actual reading while up towards the meniscus will make it look lower than the actual value
3. Pouring in the liquid too rapidly into the buret forming droplets on the inner walls of the buret which can alter the volume reading of the buret when the drops settle into the remaining liquid in the buret
