19) 15 <= 9 + 3x
15) x = 23,24,25
17) x <= 115
9) Second line
11) g > 20, don't fill in dot, any number greater than 20
1) -3 + h<= 3.4
3) No, x > -2
5) x > 14, don't fill in dot, any number greater than 14
7) k<=20, fill in dot, 20 or any larger number
(took me while to type this out lol cause on mobile)
Top triangle((6X9)/2)=27square 7x9=63 parallelogram 7X9=69 right triangle ((7X6)/2)=21 so 27+63+63+21=174
Answer:
Option B
Option E
Step-by-step explanation:
By the use of following postulates we can prove the two right triangles to be congruent.
1). HA - [Equal hypotenuse and an cute angles]
2). LL - [Two legs should be equal]
3). LA - [One leg and one angle must be equal]
4). ASA - [Two angles and the side containing these angles should be equal]
In the given right triangles,
1). OJ ≅ IL
2). ∠O ≅ ∠I
3). ∠J ≅ ∠L
Therefore, two postulates HA, ASA will be applicable for the congruence of the two triangles given.
Options A and E will be the answer.
