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Ainat [17]
3 years ago
14

A gas with volume of 700.0 mL at STP (0.0 0C, 1.00 atm) is compressed to a volume of 200.0 mL and the temperature is increased t

o 30.0 0C. What is the new pressure in kPa?
Chemistry
1 answer:
tekilochka [14]3 years ago
6 0

Answer:

393.1 KPa

Explanation:

Now we have to use the general gas equation;

P1V1/T1 = P2V2/T2

P1= initial pressure of the gas= 1.00atm

V1 = initial volume= 700.0 ml

T1= initial temperature= 0.0°C +273= 273K

V2= final volume= 200.0 ml

T2= final temperature =30.0°C +273= 303 K

P2= final pressure =????

Therefore;

P2= P1V1T2/ V2T1

P2= 1.00 × 700.0 × 303/ 200.0 × 273

P2= 3.88 atm

But

1 atm = 101.325 kilopascals

Therefore 3.88 atm = 3.88 × 101.325 kilopascals = 393.1 KPa

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In the Formula 3H2O what is the 3 called
vekshin1

Its very simple .

3H2O ---- three H two O

Its  3 molecules of water

3 0
2 years ago
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A gas sample is found to contain 39.10% carbon, 7.67% hydrogen, 26.11% oxygen, 16.82% phosphorus, and 10.30% fluorine. If the mo
Doss [256]

Answer:

C6H14O3F

Explanation:

The first step is to divide each compound by its molecular weight

Carbon

= 39.10/12

= 3.258

Hydrogen

= 7.67/1

= 7.67

Oxygen

= 26.11/16

= 1.63

Phosphorous

= 16.82/31

= 0.542

Flourine

= 10.30/19

= 0.542

The next step is to divide by the lowes value

3.258/0.542

= 6 mol of C

7.67/0.542

= 14 mol of H

1.63/0.542

= 3 mol of O

0.542/0.542

= 1 mol of P

0.542/0.542

= 1 mol of F

Hence the molecular formula is C6H14O3F

5 0
2 years ago
Unknown element x is a metal that ionically bonds to sulfur.is the formula, x3s feasible? why or why not?a)it is feasible. the t
nasty-shy [4]
The correct answer is:
d) No, it is not feasible. three metallic ions cannot provide the exact number of electrons that one sulfur needs for the ionic bond.
Because Sulfur is divalent so it need to gain 2 electrons from metal so if we have 3 metals they can't provide only two electrons only.
8 0
3 years ago
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Gold has a molar (atomic) mass of 197 g/mol. consider a 2.47 g sample of pure gold vapor. (a) calculate the number of moles of g
adell [148]
N = given mass/ molar mass.
n = number of moles
given mass = 2.47 g
molar mass = 197 g/mol

n = 2.47 / 197 
n = 0.01253 moles.
I'm sure you wanted to ask more than this. Just put some comments in. I can do the same.
3 0
3 years ago
What is the mole fraction of NaCl in a mixture containing 7.21 moles NaCl, 9.37 moles KCL, and 3.42
GrogVix [38]

Answer : The mole fraction of NaCl in a mixture is, 0.360

Explanation : Given,

Moles of NaCl = 7.21 mole

Moles of KCl = 9.37 mole

Moles of LiCl = 3.42 mole

Now we have to calculate the mole fraction of NaCl.

\text{Mole fraction of }NaCl=\frac{\text{Moles of }NaCl}{\text{Moles of }NaCl+\text{Moles of }KCl+\text{Moles of }LiCl}

Now put all the given values in this formula, we get:

\text{Mole fraction of }NaCl=\frac{7.21}{7.21+9.37+3.42}=0.360

Therefore, the mole fraction of NaCl in a mixture is, 0.360

3 0
3 years ago
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