Answer is 10(2k+5)
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Work Shown:
20k+50 = 10*2k + 10*5
20k+50 = 10(2k+5)
Note how we can distribute the 10 back in to check our work
10(2k+5) = 10(2k)+10(5) = 20k+50
so that confirms we have the right answer
Another thing to notice is that 10 is the largest factor that we can pull out of 20k and 50. The value 10 is the GCF (greatest common factor) of 20 and 50.
1 because you replace x with 2 so, (2)squared -5x2 + 7 = 4 - 10 + 7 = 1
9514 1404 393
Answer:
d. f(2) < g(2)
Step-by-step explanation:
The attached table and graph shows how the functions relate for the various x-values of interest. The true statement is ...
f(2) < g(2)
-3 < 0