Question

A 2400-kg satellite is in a circular orbitaround a planet. The

Answer 1

Answer

given,

mass of satellite = 2400 Kg

speed of the satellite =  6.67 x 10³ m/s

acceleration of satellite = ?

gravitational force of the satellite will be equal to the centripetal force

$F = \dfrac{mv^2}{r}$

$F = \dfrac{2400\times (6.67\times 10^3)^2}{r}$

Assuming the radius of circular orbit = 8.92 x 10⁶ m

now,

$F = \dfrac{2400\times (6.67\times 10^3)^2}{8.92\times 10^6}$

F = 11970.11 N

acceleration,

$a = \dfrac{F}{m}$

$a = \dfrac{11970.11}{2400}$

  a = 4.98 m/s²