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mrs_skeptik [129]
3 years ago
15

Find the greatest common factor of the following 45m 6m5

Mathematics
1 answer:
lisabon 2012 [21]3 years ago
8 0
45m 6m^5 usually helps to list the factors of each number first,
1x45=453x15=455x9=45
1x6=62x3=6
so the biggest number that fits into both would be 3, and the biggest amount you can take of any variable would be the amount of that lowest variable. when given an "m" and "m^5", you can only take out one "m", because when m÷m=1, that means you can't take any more "m's" out. if it were m^2 and m^5 you would take out m^2 :)
so your final answer would be"3m" and if you were taking it out of an equation (if you had 45m+/-6m^6)would look like 3m(15+/-2m^4
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(4x2 – 6x + 2) + (-5x2 + 6x – 6)
lys-0071 [83]
(4*2-6x+2)+(-5x2+6x-6)
8-6x+2+(-5)*2+6x-6
8-6x+2-10+6x-6
\not 10-6x-\not10+6x-6
-6x+6x-6
-6
The answer is: -6

3 0
3 years ago
PLEASE HURRY
jek_recluse [69]
C is the answer i believe
5 0
3 years ago
Read 2 more answers
What’s 40% of $600 ?
Mandarinka [93]

Answer:

$240

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
WILL GIVE BRAINLIEST FASTTTTT
Stells [14]

Answer: (x−2)(x−2)

The middle number is -4 and the last number is 4.

Factoring means we want something like

(x+_)(x+_)

Which numbers go in the blanks?

We need two numbers that...

Add together to get -4

Multiply together to get 4

Can you think of the two numbers?

Try -2 and -2:

-2+-2 = -4

-2*-2 = 4

Fill in the blanks in

(x+_)(x+_)

with -2 and -2 to get...

(x-2)(x-2)

Answer:

(x−2)(x−2)

so the answer is D.

6 0
3 years ago
Josh attempted 56 free throws during the basketball season. He made 57 of them. How many free throws did he make?
Scorpion4ik [409]

Answer:

He made approximately 32 free throws.

Step-by-step explanation:

Assuming that there's a typo in the question and that he made 57% of his attempted free throws, then we can solve it as shown below:

We can apply a rule of three in order to calculate the number of free throws he made. This is done as follows:

56 free throws -> 100%

x free throws -> 57%

56/x = 100/57

100*x = 57*56

x = 57*56/100 = 31.92

It can also be solved by transforming the percentage in a fraction such as 57% = 57/100 and then multiplying it by the total attempts.

free throws made = 56*57/100 = 31.92

He made approximately 32 free throws.

7 0
3 years ago
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