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3 years ago

PLEASE HELP 15 PTS HELP ME WITH TRUE OR FALSE MATH

Mathematics

1 answer:

Sever21 [200]3 years ago

8 0

1st on the top right hand corner is True
2nd on the second row to the right is True
3rd on the first row, second column is False
4th on the second column second row is False
5th on the third column, first row is True
6th on the third column, second row is True

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Find the area of the shaded region. Round your answer to the nearest tenth.

Troyanec [42]

Area of the square = (9 m)^2 = 81 m^2

The four circular sectors combine to form a circle with diameter 9 m, hence radius 4.5 m.

Area of the circle = π (4.5 m)^2 = 20.25π m^2

Then the area of the shaded region is

81 m^2 - 20.25π m^2 ≈ 17.4 m^2

7 0

3 years ago

Hi! Can you help me? Don’t forget about the work. Thank you so much.

Elan Coil [88]

See the attached picture:

8 0

3 years ago

Koto’s average velocity along her route was 4. 5 m/s. She started at her house and traveled 15,000 meters north, 5,000 meters ea

Lostsunrise [7]

The time taken for her trip is 3 hours.

<h3>Given that</h3>

Koto’s average velocity along her route was 4. 5 m/s.

She started at her house and traveled 15,000 meters north, 5,000 meters east, 20,000 meters south, and then 5,000 meters west.

<h3>We have to determine</h3>

What was the time of her trip?

<h3>According to the question</h3>

She started at her house and traveled 15,000 meters north, 5,000 meters east, 20,000 meters south, and then 5,000 meters west.

<h3 /><h3>The calculation of such a trip of Koto can be done by applying the known formula of Time when the Speed is multiplied by Distance to compute the actual time of the trip.</h3>

The formula to calculate the time for her trip is;

$\rm Speed = \dfrac{ Distance}{Time}\\
\\
Time = \dfrac{Distance}{Speed}\\
\\
$

Using the formula above, the commute in each direction is added as 45000 meters or 45 kilometers.

If Koto's average speed is 4.5 meters per second, then she travels roughly 270 meters in one minute.

Substitute all the values in the formula;

$\rm\ Time = \dfrac{Distance}{Speed}\\\\ Time = \dfrac{45000}{270}\\
\\
Time =166.7$

Converting minutes into hours,

$\rm Hours = \dfrac{Minute}{60}\\
\\
Hours = \dfrac{166.7}{60}\\
\\
Hours = 2.77 \\
\\
= 3\ hours$

Hence, the time taken for her trip is 3 hours.

To know more about Time and Distance click the link given below.

brainly.com/question/4433818

5 0

3 years ago

Solve the equation for the unkown variable<br> 1) -1/x=-7/2+2/x

lakkis [162]

Hope this might help

6 0

3 years ago

Read 2 more answers

(I've been trying to figure this out for 3 days and I really need help)

liq [111]

Check the picture below.

since the diameter of the cone is 6", then its radius is half that or 3", so getting the volume of only the cone, not the top.

$\bf \textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=3\\ h=4 \end{cases}\implies V=\cfrac{\pi (3)^2(4)}{3}\implies V=12\pi \implies V\approx 37.7$

now, the top of it, as you notice in the picture, is a semicircle, whose radius is the same as the cone's, 3.

$\bf \textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=3 \end{cases}\implies V=\cfrac{4\pi (3)^3}{3}\implies V=36\pi \\\\\\ \stackrel{\textit{half of that for a semisphere}}{V=18\pi }\implies V\approx 56.55$

well, you'll be serving the cone and top combined, 12π + 18π = 30π or about 94.25 in³.

pretty much the same thing, we get the volume of the cone and its top, add them up.

$\bf \stackrel{\textit{cone's volume}}{\cfrac{\pi (3)^2(8)}{3}}~~~~+~~~~\stackrel{\stackrel{\textit{half a sphere}}{\textit{top's volume}}}{\cfrac{4\pi 3^3}{3}\div 2}\implies 24\pi +18\pi \implies 42\pi ~~\approx~~131.95~in^$

8 0

3 years ago