Whcich expression are equivialant to the one below 3^4*3^x

A. Complete the chart based on the initial conditions:

Nata [24]

Answer:

a.

$Month\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ Pop(whole \ ant)\\month1 => x_1=80\times0.94^1=1128\\month2=>x_2=1200\times0.94^2=1060\\month3=>x_3=1200\times0.94^3=996\\month4=>x_4=1200\times0.94^4=936$

b.

$week Number\ \ \ \ \ \ \ \ \ \ \ \ \ \ Mass(g)\\week1 => x_1=80\times1.1^1=88g\\week2=>x_2=80\times1.1^2=96.8g\\week3=>x_3=80\times1.1^3=106.48g\\week4=>x_4=80\times1.1^4=117.128g$

Step-by-step explanation:

a. From the information provided, we can deduce that the population death's follows a Geometric sequence in the form $(a,ar,ar^2,ar^3...)$ where $a-first \ term$ and $r-common \ ratio$

#Since the population is reducing, $r$ can is obtained as $r=1-r=0.94$

#The $n^t^h$ term is obtained using the formula $x_n=ar^(^n^-^1^)$ , given a=1200

The number of ants alive after every month (in first 4 months)

$Month\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ Pop(whole \ ant)\\month1 => x_1=80\times0.94^1=1128\\month2=>x_2=1200\times0.94^2=1060\\month3=>x_3=1200\times0.94^3=996\\month4=>x_4=1200\times0.94^4=936$

The ant's alive after 4 months is obtained as the value of $x_5$

$x_n=ar^(^n^-^1^)\\1-x_5=1-1200\times 0.94^4=936.89\\\approx 936$

Hence, 936 ants are alive after 4 months.

b. As with the above question, the kitten population follows a geometric sequence: $(a,ar,ar^2,ar^3...)$ .

#Since it's a growing population , the common ration is the sum of 100% + the growth rate,

$r=1.1$ and $a=80$ and $x_n=ar^(^n^-^1^)$

The population after 4weeks will be:

$week Number\ \ \ \ \ \ \ \ \ \ \ \ \ \ Mass(g)\\week1 => x_1=80\times1.1^1=88g\\week2=>x_2=80\times1.1^2=96.8g\\week3=>x_3=80\times1.1^3=106.48g\\week4=>x_4=80\times1.1^4=117.128g$

8 0

4 years ago

In ΔEFG, the measure of ∠G=90°, FG = 2.3 feet, and EF = 6.4 feet. Find the measure of ∠F to the nearest degree.

kondaur [170]

Answer:

69 degrees

Step-by-step explanation:

7 0

4 years ago

Mr. Smith wants to order some pizza and cheese pizza cost $11 and pepperoni pizza cost $12.50 if you bought 13 pieces total and

Triss [41]

Answer: Mr Smith bought 7 pepperoni pizza

Step-by-step explanation:

Step 1

cost of cheese pizza =$11

pepperoni pizza cost =$12.50

let number cheese pizza be represented as c

and number of pepperoni pizza be represented as p

such that the total number of pizza bought which equals 13 can be represented as

c+ p= 13

and total cost of both pizza can be expressed as

11c+ 12.50p =153.50

Step 2 Solving

c+ p= 13

11c+ 12.50p =153.50

By elimination method, Multiply equation 1 by 11 and subtract the new equation from equation 2

11c+ 12.50p =153.50

11c+ 11p=143.

1.5p =10.5

p= 10.5/ 1.5 =7

c+ p= 13

c= 13-p =13-7=6

Therefore Mr Smith bought 6 cheese pizza and 7 pepperoni pizza

6 0

3 years ago

In the right triangle shown below, what is the sine of angle θ?

algol [13]

Step-by-step explanation:

In given rt.angled triangle,

Sin thita =p/h

=26.1/28.7

=0.9094

So correct answer is option D.

3 0

3 years ago

Which of the following are true?

coldgirl [10]

The answer is D because if you get the same answers from each shape that is congruent

7 0

4 years ago