Answer:
<h2>Which of the following statements correctly describes a difference between mechanical waves and electromagnetic waves?</h2><h2><em>
:- Mechanical waves require a medium to travel through, whereas electromagnetic waves can travel through empty space.</em></h2>
<em>is the correct</em>
<em>pls mark me as brainliest pls </em>
<em></em>
<h3 />
Answer:
We need 8.11 grams of glucose for this solution
Explanation:
Step 1: Data given
Molarity of the glucose solution = 0.300 M
Total volume = 0.150 L
The molecular weight of glucose = 180.16 g/mol
Step 2: Calculate moles of glucose in the solution
Moles glucose = molarity solution * volume
Moles glucose = 0.300 M * 0.150 L
Moles glucose = 0.045 moles glucose
Step 3: Calculate mass of glucose
MAss glucose = moles glucose* molecular weight of glucose
MAss glucose = 0.045 moles * 180.16 g/mol
MAss glucose = 8.11 grams
We need 8.11 grams of glucose for this solution
Answer:
(1) cathode: Y
(2) anode X
(3) electrons in the wire flow toward: Y
(4) electrons in the wire flow away from: X
(5) anions from the salt bridge flow toward X
(6) cations from the salt bridge flow toward Y
(7) gains mass: Y
(8) looses mass X
Explanation:
The voltaic cell uses two different metal electrodes, each in an electrolyte solution. The anode will undergo oxidation and the cathode will undergo reduction. The metal of the anode will oxidize, going from an oxidation state of 0 (in the solid form) to a positive oxidation state, and it will become an ion. At the cathode, the metal ion in the solution will accept one or more electrons from the cathode, and the ion’s oxidation state will reduce to 0. This forms a solid metal that deposits on the cathode. The two electrodes must be electrically connected to each other, allowing for a flow of electrons that leave the metal of the anode and flow through this connection to the ions at the surface of the cathode. This flow of electrons is an electrical current that can be used to do work, such as turn a motor or power a light.
Answer:
Explanation:
depending on the activity series there will probably be a single replacement reaction possibly heat or color change and the copper precipitate out of solution
