Answer:

Explanation:
Quantity of heat required by 10 gram of ice initially warm it from -5°C to 0°C:

here;
mass, m = 10 g
specific heat capacity of ice, 
change in temperature, 


Amount of heat required to melt the ice at 0°C:

where, 
we know that no. of moles is = (wt. in gram)
(molecular mass)


Now, the heat required to bring the water to 70°C from 0°C:

specific heat of water, 
change in temperature, 


Therefore the total heat required to warm 10.0 grams of ice at -5.0°C to a temperature of 70.0°C:



