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timofeeve [1]
3 years ago
14

Find the distance between (0,-2), (-5,-1)

Mathematics
1 answer:
svlad2 [7]3 years ago
5 0

\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\(\stackrel{x_1}{0}~,~\stackrel{y_1}{-2})\qquad(\stackrel{x_2}{-5}~,~\stackrel{y_2}{-1})\qquad \qquadd = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}\\\\\\d=\sqrt{[-5-0]^2+[-1-(-2)]^2}\implies d=\sqrt{(-5-0)^2+(-1+2)^2}\\\\\\d=\sqrt{(-5)^2+1^2}\implies d=\sqrt{26}\implies d\approx 5.099

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Assignment: \bold{Simplify \ Equation: \ 7\left(3\sqrt{2}x\right)-3\left(3\sqrt{16}x\right)-3\left(3\sqrt{8}x\right)}

<><><><><><><>

Answer: \boxed{\bold{3\sqrt{2}x-36x}}

<><><><><><><>

Explanation: \downarrow\downarrow\downarrow

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[ Step One ] Remove Parenthesis (a) = a

\bold{7\cdot \:3\sqrt{2}x-3\cdot \:3\sqrt{16}x-3\cdot \:3\sqrt{8}x}

[ Step Two ] Simplify Equations

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[ Step Three ] Rewrite Equation

\bold{21\sqrt{2}x-36x-18\sqrt{2}x}

[ Step Four ] Add Similar Elements

\bold{21\sqrt{2}x-18\sqrt{2}x=3\sqrt{2}x}

[ Step Five ] Rewrite Equation

\bold{3\sqrt{2}x-36x}

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