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kondor19780726 [428]

4 years ago

9

Plz help me with this

2 answers:

Blababa [14]4 years ago

6 0

A is the answer for this because 2 x can’t go into 2 ya

sertanlavr [38]4 years ago

6 0

The relation that is not a function would be B. If any of the inputs have at least one different output, then it is a function. Therefore, both A and C are functions. However, B is not a function because both the input -4 and 3 have the same output of -5. Therefore, B is the relation that is not a function.

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What is the answer to <img src="https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B1000%7D" id="TexFormula1" title="\sqrt[3]{1000}" alt="\

liubo4ka [24]

Therefore, cube root of 1000 is 10.

Step-by-step explanation:

= 3√1000

= 3√(10 × 10 × 10)

= 3√(103)

= 10

6 0

3 years ago

For the cost function c equals 0.1 q squared plus 2.1 q plus 8, how fast does c change with respect to q when q equals 11? Det

Soloha48 [4]

Answer:

Rate of change of c with respect to q is 4.3

Percentage rate of change c with respect to q is 9.95%

Step-by-step explanation:

Cost function is given as, $c=0.1\:q^{2}+2.1\:q+8$

Given that c changes with respect to q that is, $\dfrac{dc}{dq}$ . So differentiating given function,

$\dfrac{dc}{dq}=\dfrac{d}{dq}\left (0.1\:q^{2}+2.1\:q+8 \right)$

Applying sum rule of derivative,

$\dfrac{dc}{dq}=\dfrac{d}{dq}\left(0.1\:q^{2}\right)+\dfrac{d}{dq}\left(2.1\:q\right)+\dfrac{d}{dq}\left(8\right)$

Applying power rule and constant rule of derivative,

$\dfrac{dc}{dt}=0.1\left(2\:q^{2-1}\right)+2.1\left(1\right)+0$

$\dfrac{dc}{dt}=0.1\left(2\:q\right)+2.1$

$\dfrac{dc}{dt}=0.2\left(q\right)+2.1$

Substituting the value of $q=11$ ,

$\dfrac{dc}{dt}=0.2\left(11\right)+21.$

$\dfrac{dc}{dt}=2.2+2.1$

$\dfrac{dc}{dt}=4.3$

Rate of change of c with respect to q is 4.3

Formula for percentage rate of change is given as,

$Percentage\:rate\:of\:change=\dfrac{Q'\left(x\right)}{Q\left(x\right)}\times 100$

Rewriting in terms of cost C,

$Percentage\:rate\:of\:change=\dfrac{C'\left(q\right)}{C\left(q\right)}\times 100$

Calculating value of $C\left(q \right)$

$C\left(q\right)=0.1\:q^{2}+2.1\:q+8$

Substituting the value of $q=11$ ,

$C\left(q\right)=0.1\left(11\right)^{2}+2.1\left(11\right)+8$

$C\left(q\right)=0.1\left(121\right)+23.1+8$

$C\left(q\right)=12.1+23.1+8$

$C\left(q\right)=43.2$

Now using the formula for percentage,

$Percentage\:rate\:of\:change=\dfrac{4.3}{43.2}\times 100$

$Percentage\:rate\:of\:change=0.0995\times 100$

$Percentage\:rate\:of\:change=9.95%$

Percentage rate of change of c with respect to q is 9.95%

7 0

3 years ago

Find m∠H. Put the answer below.<br> m∠H =

max2010maxim [7]

Answer:

30 degrees

Step-by-step explanation:

This is the third time I am answering the same question asked by you.

5 0

2 years ago

-5/2/-19/10 <br><br><br> Pls Answer this question I can't figure it out!!!

Rus_ich [418]

Answer:

decimal result is 0.6 but fraction wise its 3/5

7 0

3 years ago

A FIGURE HAS AN AREA OF 50 UNITS.WHAT WILL THE NEW AREA BE AFTER A DILATION WITH SCALE FACTOR OF 3

xenn [34]

Answer:

150 units

Step-by-step explanation:

50 x 3 = 150

6 0

3 years ago