The centripetal acceleration is the ratio of the tangential speed and the
radius of the shell.
The tangential speed of the part of the shell is approximately <u>0.12961 m/s</u>
Reasons;
The widest diameter of the egg, d = 12 cm = 0.12 m
The given centripetal acceleration,
= 0.28 m/s²
Required:
The tangential speed of the bird.
Solution;

Where;

v = The tangential speed
Which gives;


v² = 0.28 m/s² × 0.06 m = 0.0168 m²/s²
v = √(0.0168 m²/s²) ≈ 0.12961 m/s
The tangential speed, v = <u>0.12961 m/s</u>
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Learn more about centripetal acceleration here:
brainly.com/question/79801
Answer:
They must have been traveling at 5333.33 km/h to cover that distance in 3 days.
That speed are 6,66 times higher than the speed of an aircraft jet.
Explanation:
d= 384000 km
t= 3 days = 3*24hr = 72hr
V= 384000km/72hr
V= 5333.33 km/h
comparison:
V1/V2= 5333.33/800
V1/V2= 6.66
Answer:
a= -0.83m\s^2
Explanation:
a = v \ t
a = -25 \ 30 = -0.833 m\s^2
the object is slowing down 0.83 meter every second
Energy resources that cannot be replaced are called "non-renewable" energy resources.
Answer:
One way to test the hypothesis is to create two waves, one in the air and one on the ground at the same time. One of them for the elephant to get closer and another for the elephants to move away. Observe the reaction of the animal and with this we know which sound came first.
Explanation:
This hypothesis is based on the fact that the speed of sound in air is v = 343 m / s with a small variation with temperature.
The speed of sound in solid soil is an average of the speed of its constituent media, giving values between
wood 3900 m / s
concrete 4000 m / s
fabrics 1540 m / s
earth 5000 m / s wave S
ground 7000 m / s P wave
we can see that the speed on solid earth is an order of magnitude greater than in air.
One way to test the hypothesis is to create two waves, one in the air and one on the ground at the same time. One of them for the elephant to get closer and another for the elephants to move away. Observe the reaction of the animal and with this we know which sound came first.
From the initial information, the wave going through the ground should arrive first.