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podryga [215]
4 years ago
14

What effect does a tripling of the net force have upon the acceleration of the object?

Physics
1 answer:
dsp734 years ago
4 0
The formula of net Force is:F = mawhere m is the mass of the objecta is the acceleration of the object
thus, if we triple the net force applied to the object:
3F = maa = 3F / m
The acceleration is also tripled since the force is directly proportional to the acceleration.


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A net force applied to a 15.0 kg box produced an acceleration of 4.2 m/s2. If the same net force was applied to a 10 kg box, wha
igor_vitrenko [27]

Answer:

6.3\ m/s^2

Explanation:

Given that,

If the mass of a body is 15 kg and produced an 4.2 m/s², we need to find the acceleration if the mass is 10 kg and the same force is applied.

Force is given by :

F = ma

Since force is same

m_1a_1=m_2a_2\\\\a_2=\dfrac{m_1a_1}{m_2}\\\\a_2=\dfrac{15\times 4.2}{10}\\\\a=6.3\ m/s^2

So, if the mass is 10 kg, acceleration is 6.3\ m/s^2

8 0
3 years ago
How much does a 45 kg rock weigh
bazaltina [42]

Answer:

441.45N

Explanation:

Weight = mass(kg) x acceleration (m/s^2)

Weight = 45kg x 9.81m/s^2=441.45N

Recall that weight =mass of the rock x gravitational force acting on the rock

Therefore, the rock will weigh = 441.45N

7 0
3 years ago
An object is dropped from rest from a height of 4.4 107 m above the surface of the Earth. If there is no air resistance, what is
kondaur [170]

Answer:

Explanation:

An object is drop from a height, then it is in direction of gravity

g is +ve

When an object drop from a height, the initial velocity is 0,

U=0

Given that h=4.4×10^7m

V=?

g=9.81m/s^2

Then using equation of motion

V^2=U^2+2gh

V^2=0+2×9.81×4.4×10^7

V^2=86.33×10^7m/s

Take square root of both side

V=29381.63m/s

Now to km/s, divide by 1000

Since 1km=1000m

V=29.38km/s

6 0
3 years ago
If a current of 2.4 a is flowing in a cylindrical wire of diameter 2.0 mm, what is the average current density in this wire?
Gnom [1K]

The average current density in the wire is given by:

J=\frac{I}{A}

where I is the current intensity and A is the cross-sectional area of the wire.


The cross-sectional area of the wire is given by:

A=\pi r^2

where r is the radius of the wire. In this problem, r=\frac{d}{2}=\frac{2.0 mm}{2}=1.0 mm=0.001 m, so the cross-sectional area is

A=\pi (0.001 m)^2=3.14 \cdot 10^{-6} m^2


and the average current density is

J=\frac{I}{A}=\frac{2.4 A}{3.14 \cdot 10^{-6} m^2}=7.64 \cdot 10^5 A/m^2

8 0
3 years ago
Read 2 more answers
A researcher determined the amount of electrical energy entering a neon lighted sign and compared it with the amount of light pr
andriy [413]

The best explanation of the observation of the researcher is that some of the energy is converted into thermal energy (option C).

<h3>How does energy transfer?</h3>

Energy, according to the law of conservation of energy, cannot be created nor destroyed but transformed.

According to this question, a researcher found that the amount of light energy produced in a neon lighted sign was less than the amount of electrical energy used.

This suggests that some of the energy is converted into thermal energy.

Learn more about energy at: brainly.com/question/1932868

#SPJ1

3 0
2 years ago
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