Answer:
The resulting magnetic force on the wire is -1.2kN
Explanation:
The magnetic force on a current carrying wire of length 'L' with current 'I' in a magnetic field B is
F = I (L*B)
Finding (L * B) , where L = (2, 0, 0)m , B = (30, -40, 0)
L x B =
= (0, 0, -80)
we can now solve
F = I (L x B) = I (-80)
F = -1200 kmN
F = -1200 kN * 10⁻³
F = -1.2kN
Mechanical
waves are oscillation of matter, they are important because they all
transfer energy from one place to another. There are 2 types of
mechanical waves. A transverse wave where the particles vibrate
perpendicular to the direction of energy travel and a longitudinal
wave where particle vibrations are parallel to the direction of the
energy transfer.
I
hope it helps, Regards.
The answer to your question is Metal