Answer:
Explanation:
The velocity of a wave in a string is equal to:
v = √(T / (m/L))
where T is the tension and m/L is the mass per length.
To find the mass per length, we need to find the cross-sectional area of the thread.
A = πr² = π/4 d²
A = π (3.0×10⁻⁶ m)²
A = 2.83×10⁻¹¹ m²
So the mass per length is:
m/L = ρA
m/L = (1300 kg/m³) (2.83×10⁻¹¹ m²)
m/L = 3.68×10⁻⁸ kg/m
So the wave velocity is:
v = √(T / (m/L))
v = √(7.0×10⁻³ N / (3.68×10⁻⁸ kg/m))
v ≈ 440 m/s
The speed of sound in air at sea level is around 340 m/s. So the spider will feel the vibration in the thread before it hears the sound.
T=5s
S=5m
U=0s/m
Acceleration=m/s^2
S=ut+(1/2)(a)(5^2)
A=(25/2)=5
A=5/(25/2)
A=10/25
A=2/5
A=0.4
A=0.4m/s^2.
Facing disagreement forces scientists to prove their theories more conclusively.
Answer:
Explanation:
What is the value of a in the function's equation?
A. -2
B. -3
C. 3
D. 2
ANSWER: c.
