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3 years ago

The diagram shows the electric field around two charged objects.

Physics

2 answers:

anyanavicka [17]3 years ago

8 0

Here we have been given two charged body W and X.

We are asked to determine the nature of charge.

Before coming into conclusion, first we have to understand the electric field lines.

The electric field lines are pictorial representation of imaginary lines which are drawn to denote the electric field in a graphical way.

The electric field line starts from a positive charge and ends at a negative charge.It means for positive charges the electric field lines are outward and for negative charges the filed lines will be inward.

In the given diagram,the filed lines for W is towards W itself.The same is also in case of X.

Hence both the charges must be negative in nature.

Hence the correct answer to the question will be B i.e W negative and X: NEGATIVE.

Inessa [10]3 years ago

6 0

<h2>Answer:</h2>

The correct answer is the option B which is both points X and W are negative.

<h3>Explanation:</h3>

In the above picture it is shown that There are two points W and X. The field of lines are entering to the both points.
There is no line which went to X from W or from X to W.
This Shows that both points have the same charge either positive or negative. Because both have repulsive force to each other.
Now it is known that electric field of lines always went from positive ion and enters to negative ions.
It means both points re negative as lines are entering both points.

<h2 />

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One student made the incomplete diagram shown below to represent the relationship between igneous rocks, sediments, sedimentary

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Answer: Option (C)

Explanation: Rock cycle plays an important role in the alteration of rocks from one form to another.

Igneous rocks when undergoes high temperature and pressure condition, it transforms into a metamorphic rock.
Sedimentary rocks are formed from the sedimentation and consolidation of sediments
Igneous rocks are formed due to the crystallization of magma.

Hence the correct answer is option (C)

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3 years ago

The law of conservation of matter states that during a chemical reaction

Sveta_85 [38]

This law states that, despite chemical reactions or physical transformations, mass is conserved — that is, it cannot be created or destroyed — within an isolated system

4 0

4 years ago

Which of the following is most like an indicator of a chemical change

qaws [65]

Answer:

methyl orange, methyl red,phenoptalin, merhy red

Explanation:

all this following are indicators use to check the end point of a reaction

5 0

4 years ago

A 6.99-g bullet is moving horizontally with a velocity of +341 m/s, where the sign + indicates that it is moving to the right (s

Ratling [72]

Answer:

a). 1.218 m/s

b). R=2.8 $^{-3}$

Explanation:

$m_{bullet}=6.99g*\frac{1kg}{1000g}=6.99x10^{-3}kg$

$v_{bullet}=341\frac{m}{s}$

Momentum of the motion the first part of the motion have a momentum that is:

$P_{1}=m_{bullet}*v_{bullet}$

$P_{1}=6.99x10^{-3}kg*341\frac{m}{s} \\P_{1}=2.3529$

The final momentum is the motion before the action so:

a).

$P_{2}=m_{b1}*v_{fbullet}+(m_{b2}+m_{bullet})*v_{f}}$

$P_{2}=1.202 kg*0.554\frac{m}{s}+(1.523kg+6.99x10^{-3}kg)*v_{f}$

$P_{1}=P_{2}$

$2.529=0.665+(1.5299)*v_{f}\\v_{f}=\frac{1.864}{1.5299}\\v_{f}=1.218 \frac{m}{s}$

b).

kinetic energy

$K=\frac{1}{2}*m*(v)^{2}$

Kinetic energy after

$Ka=\frac{1}{2}*1.202*(0.554)^{2}+\frac{1}{2}*1.523*(1.218)^{2}\\Ka=1.142 J$

Kinetic energy before

$Kb=\frac{1}{2}*mb*(vf)^{2}\\Kb=\frac{1}{2}*6.99x10^{-3}kg*(341)^{2}\\Kb=406.4J$

Ratio = $\frac{Ka}{Kb}$

$R=\frac{1.14}{406.4}\\R=2.8x10^{-3}$

3 0

3 years ago

What is the speed of a wave if it has a wavelength of<br> 42 m and a frequency of 7 hertz?

Nimfa-mama [501]

Answer:

♕ $\large{ \red{ \tt{Step - By - Step \: Explanation}}}$

☃ $\underline{ \underline{ \blue{ \large{ \tt{G \: I \: V \: E\: N}}}}} :$

Frequency ( f ) = 7 Hertz
Wavelength ( λ ) = 42m

♨ $\underline {\underline{ \orange{ \large{ \tt{T \: O \: \: F \: I \: N\: D}}}} }:$

Wave velocity ( v )

☄ $\underline{ \underline{ \large{ \pink{ \tt{S\: O \: L \: U \: T\: I \: O \: N}}}}}:$

✧ $\red{ \boxed{ \large{ \purple{ \sf{Wave \: velocity(v) = Frequency(f) \times Wavelength(λ)}}}}}$

~Plug the known values and then multiply!

↦ $\large{ \tt{7 \times 42}}$

↦ $\boxed{ \boxed{ \large{ \bold{ \tt{294 \: m {s}^ {- 1} }}}}}$

☥ $\large{ \boxed{ \boxed{ \large{ \tt{Our \: Final \: Answer : \underline{ \large{ \tt{294 \: m {s}^{ - 1}}}}}}}}}$

---------------------------------------------------------------

❁ $\underline{ \large{ \red{ \tt{D\: E\: T \: A \: I \: L\: E \: D \: \: I\: N \: F \: O}}}} :$

Frequency ( f ) : The number of complete waves , set up in a medium in one second is called frequency of the wave. The SI unit of frequency is Hertz ( Hz ). For example : if a sound wave completes 15 compressions and 15 rarefactions in one second , it's frequency is 15 Hz.

Wavelength ( λ ) : The distance between two consecutive troughs or crests in a transverse wave or the distance between two consecutive compressions or rarefactions in a longitudinal wave us called wavelength. It is the distance travelled by a wave in a time equal to it's time period. It's SI unit is metre ( m ).

Wave velocity ( v ) : The velocity with which a wave propagates in a medium is called wave velocity. It's SI unit is m/s.

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♪ Hope I helped! ♡

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✎ $\underbrace{ \overbrace{ \mathfrak{Carry \: On \: Learning}}}$ ✔

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4 0

3 years ago