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nika2105 [10]
3 years ago
11

I need help I don’t understand how to do this

Mathematics
2 answers:
hichkok12 [17]3 years ago
4 0

Answer:

your answer is 7 for this problem

tatuchka [14]3 years ago
3 0

Answer:

the missing side is 7

Step-by-step explanation:

30/5=6

24/4=6

42/?=6

42/6=7

?=7

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What is the ratio of 270 miles in 6 hours
bulgar [2K]
I depends if it is asking for miles to hours or hours to miles but, doing i would do hours to miles so it would be 270:6 which simplifies to 45:1
6 0
3 years ago
Several students and adult chaperones are going on a field trip to the theater. Each student ticket cost $2 and each adult ticke
stiks02 [169]
<span>The answer to this question would be: A. the number of adults
</span>
In this question, there are 4 times as many students as adults going on the trip. If we put it into a function where s= student and a=adult, then we could get one equation:<span>
1. s=4a
</span><span>
Each student ticket cost $2 and each adult ticket cost $4. The total cost of the trip is $144. We also can get one equation for this
2. 2s+ 4a= 144

If you put the first equation into the second, you will get:
</span>2s+4a= 144
2(4a)+4a= 144

The function is already similar with <span>2(4x)+4x but it uses a instead of x. Then x = a = number of adult</span>
6 0
2 years ago
Read 2 more answers
In a certain community, 36 percent of the families own a dog and 22 percent of the families that own a dog also own a cat. In ad
zysi [14]

Answer:  a) 0.0792   b) 0.264

Step-by-step explanation:

Let Event D = Families own a dog .

Event C = families own a cat .

Given : Probability that families own a dog : P(D)=0.36

Probability that families own a dog also own a cat : P(C|D)=0.22

Probability that families own a cat : P(C)= 0.30

a) Formula to find conditional probability :

P(B|A)=\dfrac{P(A\cap B)}{P(A)}\\\\\Rightarrow P(A\cap B)=P(B|A)\times P(A)   (1)

Similarly ,

P(C\cap D)=P(C|D)\times P(D)\\\\=0.22\times0.36=0.0792

Hence, the probability that a randomly selected family owns both a dog and a cat : 0.0792

b) Again, using (2)

P(D|C)=\dfrac{P(C\cap D)}{P(C)}\\\\=\dfrac{0.0792}{0.30}=0.264

Hence, the conditional probability that a randomly selected family owns a dog given that it owns a cat = 0.264

5 0
2 years ago
Question 3: Find the vertex of - x2 - 4x + 12
tatuchka [14]

Answer:

A. (-2,16)

Hope this helps :)

4 0
3 years ago
Cómo se escribe el número 90 en egipcio
dmitriy555 [2]
If you're talking about Egyptian, you have to put 9 "ten" symbols on the paper and you get 90.
The "ten" symbol looks like a tiny arch.
7 0
3 years ago
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