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3 years ago

Does anyone know this?

Mathematics

1 answer:

natulia [17]3 years ago

3 0

Your answer, from what i can see (lol, i cant see the whole thing) would be

b³
---
a²

hope this helps

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X+y=-2 7x-4y=8 graph

Novay_Z [31]

Answer:

x+y=-2

7x-4y=8

Step-by-step explanation:

3 0

3 years ago

Use Euler's formula to find the missing number.

frutty [35]

Answer:

Step-by-step explanation:

trust me bro

6 0

3 years ago

Find the distance between the points given. (0,5) and (-5,0)

galina1969 [7]

Answer:

5 $\sqrt{2}$

Step-by-step explanation:

Calculate the distance between the points using the distance formula

d = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = (0, 5) and (x₂, y₂ ) = (- 5, 0)

d = $\sqrt{(-5-0)^2+(0-5)^2}$

= $\sqrt{(-5)^2+(-5)^2}$

= $\sqrt{25+25}$ = $\sqrt{50}$ = 5 $\sqrt{2}$ ← exact value

5 0

3 years ago

I need help solving the problem

geniusboy [140]

29 - 29 x 15= 24.65
24.65 + 24.65 x .07= 26.3755 which rounds to 26.38
The answer is $26.38

3 0

3 years ago

A major cab company in Chicago has computed its mean fare from O'Hare Airport to the Drake Hotel to be $28.75 , with a standard

bulgar [2K]

Answer:

Following are the solution to the given choices:

Step-by-step explanation:

Using chebyshev's theorem :

$\to P(|(x-\mu)|\leq k \sigma)\geq 1- \frac{1}{k^2}\\\\here \\ \to \mu=28.75\\\\ \to \sigma=4.44$

In point a)

$\to |(x-\mu)|= |20.17-28.75|=8.58 and \sigma=4.44 \\\\so, \\k= \frac{ |(x-\mu)| }{\sigma}$

$= \frac{8.58}{4.44} \\\\ =1.9 \\\\ =2$

$value= (1- \frac{1}{k^2}) \times 100 \% =75\%$

In point b)

$\to (1- \frac{1}{k^2}) \times 100 \% =84\% \\\\\to (1- \frac{1}{k^2})=0.84 \\\\\to \frac{1}{k^2} =0.16 \\\\\to \frac{1}{k}=0.4\\\\ \to k=2.5 \\\\\to |(x-\mu)| \leq k \sigma \\\\= |(x-\mu)|\leq 2.5 \times 4.44 \\\\ = |(x-\mu)|\leq 1.11 \\\\ = (28.75\pm 11.1) \\\\\to \text{fares lies between}(17.65,39.85)$

In point c)

$\to 99.7 \% \\ lie \ between=28.75 \pm z(.03)\times \sigma \\\\ =28.75\pm 2.97 \times 4.44\\\\=(28.75\pm 13.1)\\\\=(15.65,41.85)\\$

In point d)

using standard normal variate

$x=20.17\\\\ z=-2 \\\\x=37.13\\\\ z=2\\\\\to P(20.17$

8 0

3 years ago