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3 years ago

15

A rectangle has an area of 81 square centimeters. Which of the following would be the rectangle's length and width? (Area = equa

ls length×times width)

2 answers:

ICE Princess25 [194]3 years ago

4 0

The length is 9cm and the width is also 9cm

mestny [16]3 years ago

3 0

Answer:

length: 9cm

width: 9cm

Step-by-step explanation:

9×9=81

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I WILL MARK BRAINIEST<br> I got one correct there should be about one more that’s also right

Lesechka [4]

So essentially an adjacent angle is when two angles have a common side and a common vertex.

So knowing that we can determine from the picture all the adjacent angles:

D) <2 and <3 are adjacent angles

E) <1 and <3 are adjacent angles

F) <1 and <5 are adjacent angles

I hope this helps.

7 0

3 years ago

15,30, 60,... Find the 6th term.

kolbaska11 [484]

Answer:

15, 30, 60, 120, 240, <u>480</u>.

Step-by-step explanation:

You multiply the numbers by 2 to get to the next number.

For example, 15*2 is 30. 30*2 is 60. 60*2 is 120, etc..

7 0

3 years ago

Read 2 more answers

I NEED HELP PLS I WILL MARK BRAINLIEST

ANEK [815]

Answer:

$\approx 11.2\:\mathrm{in}$

Step-by-step explanation:

The swing of the tip of pendulum is creating an arc. The question is actually asking for the length of this arc. The length of an arc is given by $2r\pi\cdot \frac{\theta}{360}$ , where $r$ is the radius of the circle and $\theta$ is the angle of the arc.

In this problem, we're given:

$\theta = 40^{\circ},\\r=16$

Substituting given values, we get:

$2\cdot 16\cdot \pi \cdot \frac{40}{360}=32\pi\cdot \frac{1}{9}\approx \boxed{11.2\:\mathrm{in}}$

8 0

3 years ago

The population of a city in 2000 was 500,000 while the population of the suburbs of that city in 2000 was 700,000. Suppose that

Mnenie [13.5K]

Answer:

The population of the city in 2002 is 469,280 while the population of the suburb is 730,720.

Step-by-step explanation:

6% of the city's population moves to the suburbs (and 94% stays in the city).
2% of the suburban population moves to the city (and 98% remains in the suburbs).

The migration matrix is given as:

$A= \left \begin{array}{cc} \\ C \\S \end{array} \right\left[ \begin{array}{cc} C&S\\ 0.94&0.06 \\0.02&0.98 \end{array} \right]$

The population in the year 2000 (initial state) is given as:

$\left[ \begin{array}{cc} C&S\\ 500,000&700,000 \end{array} \right]$

Therefore, the population of the city and the suburb in 2002 (two years after) is:

$S_0A^2=\left \begin{array}{cc} [500,000&700,000]\\& \end{array} \right\left \begin{array}{cc} \end{array} \right\left[ \begin{array}{cc} 0.94&0.06 \\0.02&0.98 \end{array} \right]^2$

$A^{2} = \left[ \begin{array}{cc} 0.8848 & 0.1152 \\\\ 0.0384 & 0.9616 \end{array} \right]$

Therefore:

$S_0A^2=\left \begin{array}{cc} [500,000&700,000]\\& \end{array} \right\left \begin{array}{cc} \end{array} \right \left[ \begin{array}{cc} 0.8848 & 0.1152 \\ 0.0384 & 0.9616 \end{array} \right]\\\\=\left[ \begin{array}{cc} 500,000*0.8848+700,000*0.0384& 500,000*0.1152 +700,000*0.9616 \end{array} \right]\\\\=\left[ \begin{array}{cc} 469280& 730720 \end{array} \right]$

Therefore, the population of the city in 2002 is 469,280 while the population of the suburb is 730,720.

6 0

4 years ago

Pls helppp me with this

Annette [7]

Answer:

15

Step-by-step explanation:

Applying,

The angle bisector theorem of triangle

From the diagram,

Since ΔAMT is an issoceless triangle,

Then,

Line OA divides Line MT into two equal parts.

Therefore,

Line MO = Line OT.............. Equation 1

From the diagram,

Line MO = 4x-1, Line OT = 3x+3

Substitute into equation 1

4x-1 = 3x+3

Collect like terms

4x-3x = 3+1

x = 4.

Therefore,

OT = 3(4)+3

OT = 12+3

OT = 15

7 0

3 years ago