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LiRa [457]
4 years ago
5

0.45 x0.27 help plz i need help

Mathematics
2 answers:
Virty [35]4 years ago
6 0
The answer would be 0.1215

I'd suggest using a calculator!<span />
storchak [24]4 years ago
4 0
0.45 times 0.27 is 0.1215
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Which equation best represent Fallon’s earning in term of Donald’s earnings?
zhuklara [117]

Answer:

C. y=x+7

Step-by-step explanation:

If you add 7 to the values on the left, you'll get the values on the right.

6 0
3 years ago
Read 2 more answers
The South Coast Air Basin (Los Angeles, Orange, and San Bernardino counties) does not meet the air quality standards for carbon
Archy [21]

Answer:

0.2225 gr/mile

Step-by-step explanation:

Let's work out first the amount of CO sent out in 1990.

The population we estimated in 12.5 million people with a total of driven miles per year of about  

12.5 million*8,700 = 108,750 million miles.

With an CO emission factor of 0.9 g per mile, we would have a total of CO emitted rounding 0.9*180,750 = 97,875 million grams

Now, we must estimate the population for 2020.

Since we are assuming an exponential growth, the population in year t is given by a function

\bf P(t)= Ce^{kt}

where C and k are constants to be determined.

We can take 1980 as year 0. This way calculations are lighter. 1990 is year 10 and 2020 is year 20.

So P(0) = 10.3 and C=10.3

So far we have

\bf P(t)= 10.3e^{kt}

Given that P(10)=12.5

\bf 10.3e^{k*10}=12.5\rightarrow e^{10k}=\frac{12.5}{10.3}=1.21359\rightarrow \\10k=log(1.21359)\rightarrow k=0.01936

And the function that models the population growth is

\bf P(t)= 10.3e^{0.01936t}

We need P(20)

\bf P(20)= 10.3e^{0.01936*20}=10.3e^{0.38717}=15.17\;million

If the miles driven per person per year remains constant at 8700 mi/yr.person, then we have a total miles driven of

15.17*8,700=131,979 million miles, so the CO emitted would be 0.9*131,979=118,781.1 million grams.

The 30% of the CO sent out in 1990 is 0.3*97,875=29,362.5 million grams.

We must reduce 118,781.1 down to 29,362.5

Hence the new CO emission factor would be

29,362.5/131,979 = 0.2225 gr/mile

6 0
3 years ago
Write an equation that gives the overall equilibrium constant in terms of the equilibrium constants and . If you need to include
shutvik [7]

Answer:

The answer is "k=k_1k_{2}^2"

Step-by-step explanation:

For point 1:

4NHH_3 \ (g) +5O_2\ (g)  \leftrightharpoons  4NO\ (g) +6H_2O \ (g)..................k_1\\\\

For point 2:

2 \times(2\ NO\ (o)+O_2 \ (g)  \leftrightharpoons  2NO_2\ (g)) ..................K_2\\\\

Adding k_1 equation and  multiply by 2 in the equation k_2 so we get  \to 4NH_3\ (g) +7 O_2\ (g) \leftrightharpoons 4 NO_2\(g) +6H_2O\ (g)....... k\\\\k= k_1\times k_{2}^2\\\\k=k_1k_{2}^2\\\\

3 0
3 years ago
Please guys say me all answer correctly​
Ratling [72]

Answer:

9222521251

Step-by-step explanation:

+6261113051+

151232065+3

156

3 0
3 years ago
IS THIS CORRECT!!!????
yanalaym [24]
So if it has to be simplified, there is only one answer if all of it is positive but it has a solution to do with minus numbers which is -2 (-x-2)
8 0
3 years ago
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