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3 years ago

AB and BC are tangents of circle P. What is the value of x?

Mathematics

2 answers:

koban [17]3 years ago

7 0

There are several information's already given in the question. It is very important to look at the attached diagram very closely. The angle given in the question is 73 degrees.
Then
x = 180 - 73
= 107 degrees
I hope that this is the answer that you were looking for and the answer has actually come to your desired help.

Sladkaya [172]3 years ago

7 0

1) 107
2) 9793 miles
3) 2.25
4) FE
5) 50 mm

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Marion flipped a coin three times. What is the probability that exactly two heads appeared?

Readme [11.4K]

Probability of getting heads: 1/2

Probability to get 2 heads out of three tries is: 1/8
Work: 1/2 x 1/2 x 1/2 = 1/8

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3 years ago

In an older television set, the screen height is 0.75 times the screen width.

natima [27]

The television set has a rectangular shape. The diagonal of this rectangle along with its width and length together form a right angular triangle.
This means that we can apply the Pythagorean theorem which states that:
(diagonal)^2 = (length)^2 + (width)^2

Let the width be w. We know that the length is 0.75 times the width, this means that: length = 0.75 w

Substitute in the above equation:
(20)^2 = (0.75w)^2 + (w)^2
400 = 0.5625 w^2 + w^2
400 = 1.5625 w^2
w^2 = 256
w = 16

This means that the width of the screen is 16 in.

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3 years ago

What is true when a system of equations has infinitely many solutions?

hjlf

B. The lines coincide

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3 years ago

Suppose the number of insect fragments in a chocolate bar follows a Poisson process with the expected number of fragments in a 2

leonid [27]

Answer:

a)The expected number of insect fragments in 1/4 of a 200-gram chocolate bar is 2.55

b)0.6004

c)19.607

Step-by-step explanation:

Let X denotes the number of fragments in 200 gm chocolate bar with expected number of fragments 10.2

X ~ Poisson(A) where $\lambda = \frac{10.2}{200} = 0.051$

a)We are supposed to find the expected number of insect fragments in 1/4 of a 200-gram chocolate bar

$\frac{1}{4} \times 200 = 50$

50 grams of bar contains expected fragments = \lambda x = 0.051 \times 50=2.55

So, the expected number of insect fragments in 1/4 of a 200-gram chocolate bar is 2.55

b) Now we are supposed to find the probability that you have to eat more than 10 grams of chocolate bar before ending your first fragment

Let X denotes the number of grams to be eaten before another fragment is detected.

$P(X>10)= e^{-\lambda \times x}= e^{-0.051 \times 10}= e^{-0.51}=0.6004$

c)The expected number of grams to be eaten before encountering the first fragments :

$E(X)=\frac{1}{\lambda}=\frac{1}{0.051}=19.607 gram$ s

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3 years ago

Find the value of x in the given

qwelly [4]

Answer:

x=8

Step-by-step explanation:

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3 years ago