At the time that I'll call ' Q ', the height of the stone that was
dropped from the tower is
H = 50 - (1/2 G Q²) ,
and the height of the stone that was tossed straight up
from the ground is
H = 20Q - (1/2 G Q²) .
The stones meet when them's heights are equal,
so that's the time when
<span>50 - (1/2 G Q²) = 20Q - (1/2 G Q²) .
This is looking like it's going to be easy.
Add </span><span>(1/2 G Q²) to each side.
Then it says
50 = 20Q
Divide each side by 20: 2.5 = Q .
And there we are. The stones pass each other
2.5 seconds
after they are simultaneously launched.
</span>
True . this is called a complex substance
You would expect to find the center of gravity in a ruler in the middle because if you were to cut a ruler in half, depending on the center of gravity, you would have two equal pieces, which mean there is equal weight, meaning the middle is the center of gravity
Angel ! You have a formula, and you have an example that's
completely worked out. The ONLY POSSIBLE reason that you
could still need help is that you're letting math scare you.
I'll do 'A' for you, 'B' most of the way, and get 'C' set up.
If THAT's not enough for you to run with and finish them all,
then you and I should both be embarrassed.
Write the formula on the wall:
°F = (9/5) °C + 32°
A). Convert 35° C °F = (9/5)(35°) + 32°
(9/5)(35) = 63 °F = 63° + 32°
°F = 95°
____________________________________
B). Convert 80°F to °C
The formula: °F = (9/5) °C + 32°
°F = 80 80 = (9/5)°C + 32
Subtract 32 from each side: 48 = (9/5)°C
Multiply each side by 5 : 240 = (9) C
Now you take over:
_________________________________________
C). Convert 15°C to °F.
The formula: °F = (9/5) °C + 32°
°C = 15 °F = (9/5) 15° + 32
(9/5) (15) = 27
Go ! °F =
Answer: only the third option. [Vector A] dot [vector B + vector C]
The dot between the vectors mean that the operation to perform is the "scalar product", alson known as "dot product".
This operation is only defined between two vectors, not one scalar and one vector.
When you perform, in the first option, the dot product of any ot the first and the second vectors you get a scalar, then you cannot make the dot product of this result with the third vector.
For the second option, when you perform the dot product of vectar B with vector C you get a scalar, then you cannot make the dot product ot this result with the vector A.
The third option indicates that you sum the vectors B and C, whose result is a vector and later you make the dot product of this resulting vector with the vector A. Operation valid.
The fourth option indicates the dot product of a scalar with the vector A, which we already explained that is not defined.
