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3 years ago

I need help with 20 and 21

Mathematics

1 answer:

7nadin3 [17]3 years ago

6 0

Https://us-static.z-dn.net/files/d63/6f064638901e33bea26f4fc25a74aa69.jpg

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James left a bin outside in his garden to collect rainwater. He notices that 1 over 4 gallon of water fills 2 over 3 of the bin.

den301095 [7]

Answer:

3/8

Step-by-step explanation:

8 0

2 years ago

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81, 27, 9, 3, . . . . is this arithmetic or geometric?

laiz [17]

The answer is geometric.

Hope this helps !

6 0

3 years ago

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Find the value of x.<br> 5<br> X<br> 11<br> y

katrin [286]

The value of the variable is 4√5. Then the correct option is C.

<h3>What is the triangle?</h3>

A triangle is a three-sided polygon with three angles. The angles of the triangle add up to 180 degrees.

The similar triangles are shown in the diagram.

16 / x = x / 5

x² = 16 × 5

x = 4 √5

Then the value of the variable is 4√5.

Then the correct option is C.

More about the triangle link is given below.

brainly.com/question/25813512

#SPJ1

8 0

2 years ago

What fraction of the months begin with the letter "A"?

Anestetic [448]

2/12 because of April and August but in simplest form it would be 1/6

4 0

4 years ago

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I need help in partial fraction!! With simple explaination would be nice!

WITCHER [35]

$\dfrac{x^4-7x^2+17x-10}{x(x^2-3)}$

The degree of the numerator (4) is larger than the degree of the denominator (3), so first you need to divide. (Added screenshot of long division procedure.)

$\dfrac{x^4-7x^2+17x-10}{x(x^2-3)}=x-\dfrac{4x^2-17x+10}{x(x^2-3)}$

Now the second term can be decomposed into partial fractions.

$\dfrac{4x^2-17x+10}{x(x^2-3)}=\dfrac{r_1}x+\dfrac{r_2x+r_3}{x^2-3}$
$\dfrac{4x^2-17x+10}{x(x^2-3)}=\dfrac{r_1(x^2-3)+x(r_2x+r_3)}{x(x^2-3)}$
$4x^2-17x+10=r_1(x^2-3)+x(r_2x+r_3)$
$4x^2-17x+10=(r_1+r_2)x^2+r_3x-3r_1$
$\implies\begin{cases}r_1+r_2=4\\r_3=-17\\-3r_1=10\end{cases}\implies r_1=-\dfrac{10}3,r_2=\dfrac{22}3,r_3=-17=-\dfrac{51}3$
$\implies\dfrac{4x^2-17x+10}{x(x^2-3)}=-\dfrac{10}{3x}+\dfrac{22x-51}{x^2-3}$

So

$\dfrac{x^4-7x^2+17x-10}{x(x^2-3)}=x+\dfrac{10}{3x}-\dfrac{22x-51}{x^2-3}$

3 0

3 years ago