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3 years ago

Which of the following correctly describes the graph of y=-12x+3 ?

Mathematics

1 answer:

olga55 [171]3 years ago

6 0

Answer:

Step-by-step explanation:

The slope is -12 and the y intercept is 3. -12 is negative and 3 is positive.

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Round each amount to the nearest hundred to find the estimate of 9635 - 4891

vovikov84 [41]

Answer:

the answer is 4,744

Step-by-step explanation:

just subtract

7 0

3 years ago

(11-8)x3+7+27-3<br> (18÷3)+6+(14-8)x5<br> (11-7)x6+4+32-4

horsena [70]

The results of the arithmetic evaluations as given in the task content are; 40,42 and 62.

<h3>What are the results of the arithmetic evaluations?</h3>

The arithmetic operations above can be evaluated and simplified as follows;

(11-8)x3+7+27-3 = (3×3)+7+27-3 = 40.

(18÷3)+6+(14-8)x5 = (6)+6+(6)x5 = 42.

(11-7)x6+4+32-4 = (5×6) +4 +32-4 = 62.

Read more on arithmetic evaluations;

brainly.com/question/4694189

#SPJ1

8 0

2 years ago

Math problem need help if do 5 stars

NNADVOKAT [17]

Answer:

The ordered pair (15, 12) means that 15 pounds of beans cost $12.

Step-by-step explanation:

We know that the x-axis is the pounds of beans and the costs are the y-axis.

4 0

3 years ago

Need help with this

snow_tiger [21]

Answer:

x y

15 -1

12 0

9 1

6 2

3 3

0 4

Step-by-step explanation:

This is a function table. For a linear function, find the average rate of change between the listed points called slope. Then use the slope to fill in other inputs and outputs for the function.

$m = \frac{y_2-y_1}{x_2-x_1}=\frac{4-0}{0-12} =\frac{4}{-12} =- \frac{1}{3}$

This means for every 3 units made in the input, the function moves down 1 output.

x y

15 -1

12 0

9 1

6 2

3 3

0 4

6 0

3 years ago

Find the area of the part of the plane 3x 2y z = 6 that lies in the first octant.

gavmur [86]

The area of the part of the plane 3x 2y z = 6 that lies in the first octant is mathematically given as

A=3 √(4) units ^2

<h3>What is the area of the part of the plane 3x 2y z = 6 that lies in the first octant.?</h3>

Generally, the equation for is mathematically given as

The Figure is the x-y plane triangle formed by the shading. The formula for the surface area of a z=f(x, y) surface is as follows:

$A=\iint_{R_{x y}} \sqrt{f_{x}^{2}+f_{y}^{2}+1} d x d y(1)$

The partial derivatives of a function are f x and f y.

$\begin{aligned}&Z=f(x)=6-3 x-2 y \\&=\frac{\partial f(x)}{\partial x}=-3 \\&=\frac{\partial f(y)}{\partial y}=-2\end{aligned}$

When these numbers are plugged into equation (1) and the integrals are given bounds, we get:

$&=\int_{0}^{2} \int_{0}^{3-\frac{3}{2} x} \sqrt{(-3)^{2}+(-2)^2+1dxdy} \\\\&=\int_{0}^{2} \int_{0}^{3-\frac{3}{2} x} \sqrt{14} d x d y \\\\&=\sqrt{14} \int_{0}^{2}[y]_{0}^{3-\frac{3}{2} x} d x d y \\\\&=\sqrt{14} \int_{0}^{2}\left[3-\frac{3}{2} x\right] d x \\\\$

$&=\sqrt{14}\left[3 x-\frac{3}{2} \cdot \frac{1}{2} \cdot x^{2}\right]_{0}^{2} \\\\&=\sqrt{14}\left[3-\frac{3}{2} \cdot \frac{1}{2} \cdot x^{2}\right]_{0}^{2} \\\\&=\sqrt{14}\left[3.2-\frac{3}{2} \cdot \frac{1}{2} \cdot 3^{2}\right] \\\\&=3 \sqrt{14} \text { units }{ }^{2}$

In conclusion, the area is

A=3 √4 units ^2