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3 years ago

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Quadrilaterals L M N O and Q R S T are shown. Given that LMNO ≅ QRST, complete the statements. Side LM is congruent to side . An

gle MNO is congruent to angle .

1 answer:

deff fn [24]3 years ago

6 0

When you have two congruent figures, the vertices are listed in the same order. This means that

Side LM ≅ Side QR, Side MN ≅ Side RS, etc. The same applies for the angles.

Therefore, Side LM ≅ Side QR and Angle MNO ≅ Angle RST.

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Sociologists say the percentage of the classic music lovers is about 5%. From the survey, we know that only 83 out of 2000 peopl

disa [49]

Answer:

p value from chi square = 0.081

Step-by-step explanation:

Given that sociologists say the percentage of the classic music lovers is about 5%. From the survey, we know that only 83 out of 2000 people listen to the classic music. Let denote the proportion of the classic music lovers. The hypotheses are H0: p=0.05 vs Ha: p≠0.05

p value = 0.09

Instead of this if we do chi square

H0: Proportion of music lovers is 5% and non music lovers is 95%

Ha: Proportions are not as per the estimate

(Two tailed chi square test)

Observed 83 1917 2000

Expected 100 1900 2000

O-E -17 17 0

chi square

(O-E)^2/E 2.89 0.1521 3.0421

df =1

p value from chi square = 0.081

Though p value is not exactly the same, the conclusion in both tests are the same

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3 years ago

Find an angle such that is 4 times its complement equals 200°

allochka39001 [22]

Answer:

40 degrees

Step-by-step explanation:

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3 years ago

Read 2 more answers

What is the solution to the system of equations? 2x+4t=12

katen-ka-za [31]

Answer:

C. $(8, -1)$

Step-by-step explanation:

{y = ¼x - 3}

{2x + 4y = 12

2x + 4[¼x - 3] = 12

2x + x - 12 = 12

3x - 12 = 12

+ 12 + 12

_________

3x = 24

__ __

3 3

$x = 8$ [Plug this back into both equations above to get the y-coordinate of −1]; $-1 = y$

I am joyous to assist you anytime.

6 0

3 years ago

(3 + 8i) + (7 -- 2i) - (6 - 5i)<br> AO 4+1<br> B.O4 + 117<br> c. 16 +1<br> D.O4 + 1143

Lubov Fominskaja [6]

Answer: (3 + 8i) + (7 -- 2i) - (6 - 5i) = 4 + 15i

_____________________________________________

Simplify the expression.

4 + 15i

_____________________________________________

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3 0

2 years ago

Please solve this<br> (Rational numbers 8th grade)

pochemuha

Question # 1

Answer:

$\frac{-2}{3}\times \frac{3}{5}+\frac{5}{2}\times \frac{3}{5}\times \frac{1}{6}=-\frac{3}{20}$

Step-by-step explanation:

Given the expression

$\frac{-2}{3}\times \frac{3}{5}+\frac{5}{2}\times \frac{3}{5}\times \frac{1}{6}$

$=-\frac{2}{5}+\frac{5}{2}\times \frac{3}{5}\times \frac{1}{6}$ ∵ $\frac{-2}{3}\times \frac{3}{5}=-\frac{2}{5}$

$=-\frac{2}{5}+\frac{1}{4}$ ∵ $\frac{5}{2}\times \frac{3}{5}\times \frac{1}{6}=\frac{1}{4}$

$\mathrm{Least\:Common\:Multiplier\:of\:}5,\:4:\quad 20$

$=-\frac{8}{20}+\frac{5}{20}$

$\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}$

$=\frac{-8+5}{20}$

$\mathrm{Add/Subtract\:the\:numbers:}\:-8+5=-3$

$=\frac{-3}{20}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{b}=-\frac{a}{b}$

$=-\frac{3}{20}$

Therefore,

$\frac{-2}{3}\times \frac{3}{5}+\frac{5}{2}\times \frac{3}{5}\times \frac{1}{6}=-\frac{3}{20}$

Question # 2

Answer:

$\frac{2}{5}\times \frac{-3}{7}-\frac{1}{6}\times \frac{3}{2}\times \frac{1}{14}\times \frac{2}{5}=-\frac{5}{28}$

Step-by-step explanation:

Given

$\frac{2}{5}\times \frac{-3}{7}-\frac{1}{6}\times \frac{3}{2}\times \frac{1}{14}\times \frac{2}{5}$

$=-\frac{6}{35}-\frac{1}{6}\times \frac{3}{2}\times \frac{2}{5}\times \frac{1}{14}$ ∵ $\frac{2}{5}\times \frac{-3}{7}=-\frac{6}{35}$

$=-\frac{6}{35}-\frac{1}{140}$ ∵ $\frac{1}{6}\times \frac{3}{2}\times \frac{1}{14}\times \frac{2}{5}=\frac{1}{140}$

$\mathrm{Least\:Common\:Multiplier\:of\:}35,\:140:\quad 140$

$=-\frac{24}{140}-\frac{1}{140}$

$\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}$

$=\frac{-24-1}{140}$

$\mathrm{Subtract\:the\:numbers:}\:-24-1=-25$

$=\frac{-25}{140}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{b}=-\frac{a}{b}$

$=-\frac{25}{140}$

$\mathrm{Cancel\:the\:common\:factor:}\:5$

$=-\frac{5}{28}$

Therefore,

$\frac{2}{5}\times \frac{-3}{7}-\frac{1}{6}\times \frac{3}{2}\times \frac{1}{14}\times \frac{2}{5}=-\frac{5}{28}$

4 0

3 years ago