Hai i guess ur new here well enjoy thsi app is really Cool✊
Answer:
The answer to your question is: letter D 10 l
Explanation:
Data
V1 = 5.8 l
P1= 760 mmHg
T 0 constant
P2 = 430 mmHg
V2 = ?
Formula
V1P1 = V2P2
and we clear V2 from the equation
V2 = V1P1/P2
V2 = (5.8)(760)/430)
V2 = 10.25 l
Answer:
Explanation:
<u>1) Data:</u>
<u />
a) Acetic acid CH₃COOH
b) molar mass of CH₃COOH: 60.052 g/mol
c) %: = 5.00%
d) d = 1.006 g/ml
e) M = ?
<u>2) Formulae:</u>
a) M = n of solute / V of solution in liters
b) n = mass in grams / molar mass
c) % = (mass of solute / mass of solution)×100
d) d = mass / volume
<u>3) Solution:</u>
a)<u> Assume a basis </u>
b) <u>Calculate the mass of that basis (1 liter of solution)</u>
- d = mass / V ⇒ mass = d × V
- mass = 1.006 g/ml × 1 liter × 1,000 ml/liter = 1006 g
c) <u>Calculate the mass of solute</u>
<u />
- % = (mass of solute / mass of solution ) × 100 ⇒
mass of solute = % × mass of solution / 100 = 5.00% × 1,006 g / 100
mass of solute = 50.3 g
d) <u>Calculate the number of moles of solute</u>
<u />
- n = mass in grams / molar mass = 50.3 g / 60.052 g/mol = 0.838 mol
e) <u>Calculate molarity</u>
- M = n / V in liter = 0.838 mol / 1 liter = 0.838 M ← answer
A, because it’s chemical while the others are physical properties, this is because anything that can set on fire is chemical... While B, C, and D your physically touching it.