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olga_2 [115]
3 years ago
13

. A large quantity of very dilute aqueous HCl solution is neutralized by the addition of the stoichiometric amount of a 10-mol-%

aqueous NaOH solution. Estimate the heat effect per mole of HCl neutralized if the tank is maintained at 25°C and 1(atm) and the neutralization reaction goes to completion. ∙ For NaOH(9H2O), Δ˜H = 45.26 kJ·mol−1 ∙ For NaCl, ~ limn→[infinity]˜ΔH = 3.88 kJ·mol−1
Chemistry
1 answer:
ad-work [718]3 years ago
5 0

Answer:

Make the question more clear for me

Explanation:

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A buffer is made by dissolving H3PO4 and NaH2PO4 in water.
xeze [42]

Answer:

(a) H₃O⁺(aq) + H₂PO₄⁻(aq) ⟶ H₃PO₄(aq) + H₂O(ℓ)

(b) OH⁻(aq) + H₃O⁺(aq) ⟶ 2H₂O(ℓ)

Explanation:

The equation for your buffer equilibrium is:

H₃PO₄(aq) + H₂O(ℓ) ⇌ H₃O⁺(aq)+ H₂PO₄⁻(aq)

(a) Adding H₃O⁺

The hydronium ions react with the basic dihydrogen phosphate ions.

H₃O⁺(aq) + H₂PO₄⁻(aq) ⟶ H₃PO₄(aq) + H₂O(ℓ)

(b) Adding OH⁻

The OH⁻ ions react with the more acidic hydronium ions.

OH⁻(aq) + H₃O⁺(aq) ⟶ 2H₂O(ℓ)

4 0
3 years ago
Read 2 more answers
Why is the cell membrane essential for cell homeostasis?
Nadya [2.5K]
Hello,

Here is your answer:

The proper answer to this question is option C "To allow waste to exit the cell"! The cell membrane controls the matieral that goes in and out of the cell!

Your answer is C.

If you need anymore help feel free to ask me!

Hope this helps!
3 0
3 years ago
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What is the freezing point (in C) of a 1.56 m aqueous solution of CaCl2? (Amount to three decimal points)
Julli [10]
Supposing complete ionization: 
<span>CaCl2 → Ca{2+} + 2 Cl{-} [three ions total] </span>

<span>(1.56 m CaCl2) x (3 mol ions / 1 mol CaCl2) = 4.68 m ions </span>

<span>(1.86 °C/m) x (4.68 m) = 8.70 °C change </span>

<span>0°C - 8.70°C = - 8.70°C</span>
4 0
3 years ago
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Based on sulubility rules, which of the
CaHeK987 [17]

Answer:

The correct option is: E. No precipitate will form.

Explanation:

A solubility chart refers to the list of solubility of various ionic compounds. It shows the solubility of the various compounds in water at room temperature and 1 atm pressure.

Also, according to the solubility rules, the salts of chlorides, bromides and iodides are generally soluble and mostly all salts of sulfate are soluble.

Since, all the compounds formed in this double replacement reaction are soluble in water. Therefore, no precipitate will be formed.

ZnSO₄ (aq) + MgCl₂ (aq) → ZnCl₂ (aq) + MgSO₄ (aq)    

4 0
3 years ago
What is the ionic bonding of NaCl
madam [21]
Na has a one proton over than electrons.so Na makes a Na+
Cl has a one electron overthan protons.so Cl makes a Cl-

proton has a + affectation
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8 0
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