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Aleks [24]
3 years ago
14

The steps leading to an algal-bloom fish kill

Chemistry
1 answer:
adoni [48]3 years ago
3 0

Answer:

the bacteria increase in number and use up the dissolved oxygen in the water. When the dissolved oxygen content decreases, many fish and aquatic insects cannot survive. This results in a dead area. Algal blooms may also be of concern as some species of algae produce neurotoxins.Explanation:

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The isotopes K-37 and K-42 have the same
Masteriza [31]

Answer:

the same number of protons

Explanation:

5 0
2 years ago
Read 2 more answers
Mercury’s atomic emission spectrum is shown below. Estimate the wavelength of the orange line. What is its frequency? What is th
lions [1.4K]

The wavelength of the orange line is 610 nm, the frequency of this emission is 4.92 x 10¹⁴ Hz and the energy of the emitted photon corresponding to this <em>orange line</em> is 3.26 x 10⁻¹⁹ J.

<em>"Your question is not complete, it seems to be missing the diagram of the emission spectrum"</em>

the diagram of the emission spectrum has been added.

<em>From the given</em><em> chart;</em>

The wavelength of the atomic emission corresponding to the orange line is 610 nm = 610 x 10⁻⁹ m

The frequency of this emission is calculated as follows;

c = fλ

where;

  • <em>c is the speed of light = 3 x 10⁸ m/s</em>
  • <em>f is the frequency of the wave</em>
  • <em>λ is the wavelength</em>

f = \frac{c}{\lambda } \\\\f = \frac{3\times 10^8}{610 \times 10^{-9}} \\\\f = 4.92 \times 10^{14} \ Hz

The energy of the emitted photon corresponding to the orange line is calculated as follows;

E = hf

where;

  • <em>h is Planck's constant = 6.626 x 10⁻³⁴ Js</em>

<em />

E = (6.626 x 10⁻³⁴) x (4.92 x 10¹⁴)

E = 3.26 x 10⁻¹⁹ J.

Thus, the wavelength of the orange line is 610 nm, the frequency of this emission is 4.92 x 10¹⁴ Hz and the energy of the emitted photon corresponding to this <em>orange line</em> is 3.26 x 10⁻¹⁹ J.

Learn more here:brainly.com/question/15962928

6 0
1 year ago
What is the iupac name of this structure?
alexgriva [62]

Answer:

3–ethyl–4–methylhexane.

Explanation:

To name the above compound, do the following:

1. Determine the functional group of the compound.

2. Locate the longest continuous carbon chain. This gives the parent name of the compound.

3. Identify the substituent group attached to the compound.

4. Give the substituent the lowest possible count.

5. Combine the above to name the compound.

Now, we shall name the compound given in the question above as follow:

1. The compound contains only single bond. Therefore, the compound belong to the alkane family.

2. The longest continuous carbon chain is 6 i.e hexane.

3. The substituent group attached are:

i. Methyl, CH3.

ii. Ethyl, CH2CH3.

4. we shall name the substituents alphabetically i.e ethly will come before methyl. Therefore,

Ethyl is located at carbon 3.

Methy is located at carbon 4.

5. Therefore, the name of the compound is:

3–ethyl–4–methylhexane.

5 0
2 years ago
!HELP ASAP!!!
Snowcat [4.5K]

Answer:

Covalent Bonds

Explanation:

INTERmolecular forces are those that exist between molecules, so you can think of it liek international things taking place between countries. As you are aware, dipoles exist across an entire molecule, so for 2 dipoles to interact, there needs to be 2 molecules. Van der Waals forces also take place between  molecules when there is an uneven distribution of electrons across a molecule, causing a temporary weak dipole. Hydrogen bonding is similar to dipole-dipole forces, but only happen when there is a hydrogen interacting with an atom on another molecule that has a lone pair of electrons.

Covalent bonds, however, are INTRAmolecular, meaning they are present within a molecule. Covalent bonds are the bonds that exist when two atoms, within the same molecule, share electrons so both can have a stable electron configuration.

Hope I helped! xx

6 0
3 years ago
Read 2 more answers
Please help I need to correct I don't understand it
victus00 [196]
Answer is d. in hetrogeneous you can separate things from each other
4 0
2 years ago
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