The molality of a 0.677 m ethanol ( c 2 h 5 o h ) solution whose density is 0.588 g/ml.
What is molality and molarity?
The number of solvent moles per kilogram is known as molality. Because the mass of the solute and solvent in the solution remains constant, molality is the preferred concentration transfer method.
Molarity, also referred to as molar concentration, is the quantity of a material expressed as moles per litre of solution. Solutions marked with a molar concentration have a capital M. One mole of solvent per litre is present in a 1.0 M solution.
Molar mass (w) of C2H5OH = 46g
Molarity(M) = 0.677M
Density(D) = 0.588g/mol
<u>Molality(m)</u><u> = M/D * (1000 + w*M)</u>
<u>= 1187.2m</u>
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Answer:
Molecular formula = C₂H₄Cl₂
Explanation:
Molecular formula:
Molecular formula consist of symbols of elements present in compound with numbers of atoms of each element in subscript.
Empirical formula:
It is the simplest formula gives the ratio of atoms of different elements in small whole number .
Given data:
Percentage of hydrogen = 4.07%
Percentage of Cl = 71.65%
Percentage of carbon = 24.27%
Molar mass = 99 g/mol
Molecular formula = ?
Solution:
Number of gram atoms of H = 4.07 / 1.01 = 4.0
Number of gram atoms of Cl = 71.65 / 35.5 = 2.0
Number of gram atoms of C = 24.27 / 12 = 2.0
Atomic ratio:
H : C : Cl
4/2 : 2/2 : 2/2
2 : 1 : 1
C : H : Cl = 1 : 2 : 1
Empirical formula is CH₂Cl.
Molecular formula:
Molecular formula = n (empirical formula)
n = molar mass of compound / empirical formula mass
Empirical formula mass = 12+1×2+ 35.5 = 49.5
n = 99/49.5
n = 2
Molecular formula = n (empirical formula)
Molecular formula = 2 ( CH₂Cl)
Molecular formula = C₂H₄Cl₂
The molar mass constant is used to convert mass to moles
Analyze the Name of complex Compound.
T<span>etracarbonylplatinum(iv) chloride
So, there are,
4 Carbonyl groups = 4 CO = (CO)</span>₄
1 Platinum Metal = 1 Pt = Pt
Unknown Chloride atoms = ?
In complexes positive part is always named first, so the sphere containing Pt and carbonyl ligands is written first,
[Pt (CO)₄]
The charge on sphere is +4 because CO ligand is neutral, and Pt has a Oxidation state of four as written in name (IV),
So,
[Pt (CO)₄]⁴⁺
Now, in order to neutralize +4 charge we should add 4 Chloride ions, So,
[Pt (CO)₄] Cl₄