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Natalija [7]
3 years ago
10

Which of the following is true about a rigid body in dynamic equilibrium? The body can have translational motion, but it cannot

have rotational motion. The body can have translational motion and rotational motion, as long as its translational and angular accelerations are equal to zero. The body cannot have translational motion, but it can have rotational motion. The body cannot have translational or rotational motion of any kind.
Physics
1 answer:
mr_godi [17]3 years ago
5 0

Answer:

The correct answer is "The rigid body can have rotational and transnational motion, as long as it's transnational and angular accelerations are equal to zero."

Explanation:

A rigid body by definition does not deform when forces act on it. In case of static equilibrium a rigid body cannot have any sort of motion while in case of dynamic equilibrium it can move but with constant velocities only thus having no acceleration weather transnational or angular.

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Can inserting a resistor in a circuit produce an effect similar to a short circuit?
tresset_1 [31]

Answer:

By ‘inserting’ you means to putting a resistor in series. In this case, no, there is no resistance that would produce the same effect as a short circuit.

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6 0
2 years ago
Need QUICK answer!
Tresset [83]

Most likely the answer is B.

7 0
3 years ago
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What is the distance between a 900 kg compact car and a 1600 kg pickup truck if the gravitational force between them is about 0.
elena-14-01-66 [18.8K]

Answer:

The distance is 0.96m

Explanation:

Given

m1= 900kg

m2= 1600kg

Force F= 0.0001nN

G=6.67430*10^-11 Nm^2/kg^2

Required

The distance r

Step two:

the formula for the force is given as

F = Gm1m2/r2

make r subject of the formula

r= \sqrt{\frac{Gm1m2}{F} }

r= \sqrt{\frac{6.67430*10^-11*900*1600}{0.0001} }\\\\r= 0.00009610992/0.0001`}\\\\r= 0.96m

Answer:

The distance is 0.96m

Explanation:

Given

m1= 900kg

m2= 1600kg

Force F= 0.0001nN

G=6.67430*10^-11 Nm^2/kg^2

Required:

The distance r

Step two:

the formula for the force is given as

F = Gm1m2/r2

make r subject of the formula

r= \sqrt{\frac{Gm1m2}{F} }

r= \sqrt{\frac{6.67430*10^-11*900*1600}{0.0001} }\\\\r= 0.00009610992/0.0001`}\\\\r= 0.96m

3 0
3 years ago
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List 3 different things you can read off a motion graph.
Lunna [17]

Answer:

1) Position time graph

2) Acceleration time graph

3) Velocity time graph

6 0
3 years ago
Read 2 more answers
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