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3 years ago

an interplantetary speedcarft moving at 20000m/s.how far will it travell in one day?(give your answer in km)

Physics

1 answer:

Scilla [17]3 years ago

8 0

Explanation:

Step I: 1 day means 24 hours * 60 minutes * 60 seconds.

So 1 day have 86400 seconds.

Step I:

Now,

To calculate the travel distance 20,000m/s* 84600 is 1728000000m

Step Ill:

Now convert the meter in kilometer

Because 1 km = 1000 m

So, = 1728000000/1000 = 172800OKm

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mr_godi [17]

Answer:

$1.5 \Omega$

Explanation:

The resistance of a wire is given by the equation:

$R=\rho \frac{L}{A}$

where

$\rho$ is the resistivity of the material

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A is the cross-sectional area of the wire

In this problem, we have a wire of platinoid, whose resistivity is

$\rho = 3.3\cdot 10^{-7} \Omega m$

The length of the wire is

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And its radius is

$r=\frac{0.14 cm}{2}=0.07 cm = 7\cdot 10^{-4} m$ , so the cross-sectional area is

$A=\pi r^2=\pi(7\cdot 10^{-4})^2=1.54\cdot 10^{-6}m^2$

Solving for R, we find the resistance of the wire:

$R=(3.3\cdot 10^{-7})\frac{7.0}{1.54\cdot 10^{-6}}=1.5 \Omega$

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3 years ago

Determine the empirical formula for a compound that is 36.86% n and 63.14% o by mass.

olga2289 [7]

Answer:

$NO_{1.499}$

Explanation:

Let assume that 100 kg of the compound is tested. The quantity of kilomoles for each element are, respectively:

$n_{N} = \frac{36.86\,kg}{14.006\,\frac{kg}{kmol} }$

$n_{N} = 2.632\,kmol$

$n_{O} = \frac{63.14\,kg}{15.999\,\frac{kg}{kmol} }$

$n_{O} = 3.946\,kmol$

Ratio of kilomoles oxygen to kilomole nitrogen is:

$n^{*} = \frac{3.946\,kmol}{2.632\,kmol}$

$n^{*}= 1.499$

It means that exists 1.499 kilomole oxygen for each kilomole nitrogen.

The empirical formula for the compound is:

$NO_{1.499}$

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