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1 year ago

an interplantetary speedcarft moving at 20000m/s.how far will it travell in one day?(give your answer in km)

Physics

1 answer:

Scilla [17]1 year ago

8 0

Explanation:

Step I: 1 day means 24 hours * 60 minutes * 60 seconds.

So 1 day have 86400 seconds.

Step I:

Now,

To calculate the travel distance 20,000m/s* 84600 is 1728000000m

Step Ill:

Now convert the meter in kilometer

Because 1 km = 1000 m

So, = 1728000000/1000 = 172800OKm

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The pupil of the human eye can vary in diameter from 2.00 mm in bright light to 8.00 mm in dim light. The eye has a focal length

Zarrin [17]

The indicated data are of clear understanding for the development of Airy's theory. In optics this phenomenon is described as an optical phenomenon in which The Light, due to its undulatory nature, tends to diffract when it passes through a circular opening.

The formula used for the radius of the Airy disk is given by,

$y_r=1.22\frac{\lambda f}{d}$

Where,

$y_r =$ Range of the radius

$\lambda =$ wavelength

f= focal length

Our values are given by,

State 1:

$d=2.00mm = 2*10^{-3}m$

$f= 25mm = 25*10^{-3}m$

$\lambda = 750nm = 750*10^{-9}m$

State 2:

$d=8.00mm = 8*10^{-3}m$

$f= 25mm = 25*10^{-3}m$

$\lambda = 390nm = 390*10^{-9}$

Replacing in the first equation we have:

$y_{r1} = 1.22\frac{(750*10^{-9})(25*10^{-3})}{2*10^{-3}}$

$y_{r1}= 11.4\mu m$

And also for,

$y_{r2} =1.22\frac{(390*10^{-9})(25*10^{-3})}{8*10^{-3}}$

$y_{r2} = 1.49\mu m$

Therefor, the airy disk radius ranges from $1.49\mu m$ to $11.4\mu m$

7 0

2 years ago

Two electrodes, separated by a distance d, in a vacuum are maintained at a constant potential difference. An electron, accelerat

Alja [10]

Answer:

Explanation:

Given that, the distance between the electrode is d.

The electron kinetic energy is Ek when the electrode are at distance "d" apart.

So, we want to find the K.E when that are at d/3 distance apart.

K.E = ½mv²

Note: the mass doesn't change, it is only the velocity that change.

Also,

K.E = Work done by the electron

K.E = F × d

K.E = W = ma × d

Let assume that if is constant acceleration

Then, m and a is constant,

Then,

K.E is directly proportional to d

So, as d increase K.E increase and as d decreases K.E decreases.

So,

K.E_1 / d_1 = K.E_2 / d_2

K.E_1 = E_k

d_1 = d

d_2 = d/3

K.E_2 = K.E_1 / d_1 × d_2

K.E_2 = E_k × ⅓d / d

Then,

K.E_2 = ⅓E_k

So, the new kinetic energy is one third of the E_k

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2 years ago

The speed of light in a vacuum is 2.99x10^8 m/s. calculate its speed in miles per hour.

34kurt

You'll never get the correct answer without the correct conversion factor. Note carefully that you have no decimal. It should be
1 km = 0.6214 miles 
1000 m = 1 km 
60 seconds = 1 minute 
60 minutes = 1 hour. 
2.998E8 m/s x (1 km/1000m) x (0.6214 miles/km) x (60 sec/min) x (60 min/hr) = ?

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2 years ago

PLEASE HELP 8th grade honors science

lora16 [44]

Both of them are magnets coiled by wires.

1. The wire coiled in the first diagram, the wire is having current, Making the magnetic feild of the magnet more........

2. The wire coiling the magnet is here not having electric current making the magnetic feild smaller

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2 years ago

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Artemon [7]

Answer: methyl

Explanation:

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2 years ago