Answer:
Explanation:
The differential electric field 
due to differential charge 
at distance 
from the origin is
but since 
we have
integrating this from 
to 
we get
![E = 4k[(x_0+L)-x_0]](https://tex.z-dn.net/?f=E%20%3D%204k%5B%28x_0%2BL%29-x_0%5D)
putting in 
and 
we get
Initial angular velocity wi = 0
final angular velocity wf = 2.9 x 10⁴ rev/min
wf = 2.9 x 10⁴ (2*3.14 rad)/(60 sec)
wf = 3.035 x 10³ rad/sec
time t = 3 sec
angular acceleration α
wf = wi + αt
3.035 x 10³ = 0 + α(3)
α = 1012 rad/s²
(b) angle covered is θ
θ = wi*t + (1/2)αt²
θ = 0*3 + (1/2)(1012)(3²)
θ = 4554 rad
the answer is A and i hope its right
Let Vpa be the velocity of plane with respect to air and Vp and Va be the velocities of plane and air respectively with respect to ground.
<span>Vpa = Vp - Va </span>
<span>Vp = Vpa + Va [all these quantities are vectors] </span>
<span>so by parallelogram law of vector addition </span>
<span>Vp = (Va^2 + Vpa^2 + 2*Va*Vpa*cos120)^(1/2) </span>
<span>Vp^2 = 33^2 + 140^2 - 33*140 </span>
<span>Vp^2 = 16096 </span>
<span>Vp = 126.763m/s </span>
<span>(2) tan b = (33*sin120)/(140+33/2) </span>
<span>b = 10.34 degrees North of East </span>
<span>(3) component of velocity of plane in east = Vp cos(10.34) = 126.763*1 = 126.7m/s </span>
<span>distance travelled by plane in east = 126.7 * 60*60=456120 m</span>
Answer:
Electron.
From plastic rod to metal sphere.
Explanation:
The charged plastic rod is negatively charged, which means it contains excess electrons.
After they touch each other, the plastic rod now has a more positive value.
Since the sphere is a metal sphere, it is able to conduct the flow of electrons.
Hence, the plastic rod has given off some of its electrons to the metal sphere.
