I think you use
xamount(1-.8)
.8 being 80% as a decimal.
1 being 100%
so .2 or 20% remaining multiplied by whatever amount.
The system is
i)
ii)
The solutions to this system, are all points (x, y) for which BOTH these 2 inequalities hold.
Check the points separately:
(5, 1)
i)
True
ii)
Not True
(0, 0)
i)
True
ii)
True
(-2, -3)
i)
True
ii)
True
(2, 5)
i)
Not True
ii)
Not True
Answer: (0, 0) and (-2, -3)
The initial investment = $250
<span>annual simple interest rate of 3% = 0.03
</span>
Let the number of years = n
the annual increase = 0.03 * 250
At the beginning of year 1 ⇒ n = 1 ⇒⇒⇒ A(1) = 250 + 0 * 250 * 0.03 = 250
At the beginning of year 2 ⇒ n = 2 ⇒⇒⇒ A(2) = 250 + 1 * 250 * 0.03
At the beginning of year 3 ⇒ n = 3 ⇒⇒⇒ A(2) = 250 + 2 * 250 * 0.03
and so on .......
∴ <span>The formula that can be used to find the account’s balance at the beginning of year n is:
</span>
A(n) = 250 + (n-1)(0.03 • 250)
<span>At the beginning of year 14 ⇒ n = 14 ⇒ substitute with n at A(n)</span>
∴ A(14) = 250 + (14-1)(0.03*250) = 347.5
So, the correct option is <span>D.A(n) = 250 + (n – 1)(0.03 • 250); $347.50
</span>
Answer:
q=rs
Step-by-step explanation:
r/q=s
*r
q=rs
Answer:
uhhh yeah it is
Step-by-step explanation:
